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ollegr [7]
3 years ago
6

A 6 kg tennis ball moves at a velocity of 14 m/s. The ball is struck by a racket, causing it to rebound in the opposite directio

n at a speed of 5 m/s. What is the change in the ball’s momentum? Report the number of kg‧m/s with the appropriate sign.

Physics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0
Answer and method on photo

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In a lab experiment, a student is trying to apply the conservation of momentum. Two identical balls, each with a mass of 1.0 kg,
Studentka2010 [4]

Answer:

Second Trial satisfy principle of conservation of momentum

Explanation:

Given mass of ball A and ball B =\ 1.0\ Kg.

Let mass of ball A and B\ is\ m  

Final velocity of ball A\ is\ v_1

Final velocity of ball B\ is\ v_2

initial velocity of ball A\ is\ u_1

Initial velocity of ball B\ is\ u_2

Momentum after collision =mv_1+mv_2

Momentum before collision = mu_1+mu_2

Conservation of momentum in a closed system states that, moment before collision should be equal to moment after collision.

Now, mu_1+mu_2=mv_1+mv_2

Plugging each trial in this equation we get,

First Trial

mu_1+mu_2=mv_1+mv_2\\1(1)+1(-2)=1(-2)+1(-1)\\1-2=-2-1\\-1=-3

momentum before collision \neq moment after collision

Second Trial

mu_1+mu_2=mv_1+mv_2\\1(.5)+1(-1.5)=1(-.5)+1(-.5)\\.5-1.5=-.5-.5\\-1=-1

moment before collision = moment after collision

Third Trial

mu_1+mu_2=mv_1+mv_2\\1(2)+1(1)=1(1)+1(-2)\\2+1=1-2\\3=-1

momentum before collision \neq moment after collision

Fourth Trial

mu_1+mu_2=mv_1+mv_2\\1(.5)+1(-1)=1(1.5)+1(-1.5)\\.5-1=1.5-1.5\\-.5=0

momentum before collision \neq moment after collision

We can see only Trial- 2 shows the conservation of momentum in a closed system.

4 0
3 years ago
Read 2 more answers
WHICH ONE IS CORRECT???
sveta [45]

Answer:

A

Explanation:

5 0
2 years ago
Read 2 more answers
Compare skater's total energy at point A and at point E?(disregard the friction)
White raven [17]

Answer:

c

Explanation:

because I've had this question before and got it right

7 0
3 years ago
What does increasing the speed of an object do to its potential energy?
JulijaS [17]
It does not affect the objects potential energy.
7 0
3 years ago
Read 2 more answers
The law of repulsion by Coulomb agrees with: Newton's law of universal gravitation Newton's laws of motion the findings of Gilbe
s344n2d4d5 [400]

Explanation:

The law of repulsion is given by Coulomb. The mathematical form of Coulomb law is given by :

F=\dfrac{kq_1q_2}{r^2}...............(1)

Where

F is the force

k is the electrostatic constant

q_1\ and\ q_2 are electric charges

r is the distance between charges

The Newton's law of universal gravitation is given by :

F=\dfrac{Gm_1m_2}{r^2}..............(2)

G is the universal gravitational constant

From equation (1) and (2) it is clear that both law obeys inverse square law and both are of same type. So, the law of repulsion by Coulomb agrees with the Newton's law of universal gravitation.

7 0
3 years ago
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