A 6 kg tennis ball moves at a velocity of 14 m/s. The ball is struck by a racket, causing it to rebound in the opposite directio
n at a speed of 5 m/s. What is the change in the ball’s momentum? Report the number of kg‧m/s with the appropriate sign.
1 answer:
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Answer:
g(h) = g ( 1 - 2(h/R) )
<em>*At first order on h/R*</em>
Explanation:
Hi!
We can derive this expression for distances h small compared to the earth's radius R.
In order to do this, we must expand the newton's law of universal gravitation around r=R
Remember that this law is:
In the present case m1 will be the mass of the earth.
Additionally, if we remember Newton's second law for the mass m2 (with m2 constant):
Therefore, we can see that
With a the acceleration due to the earth's mass.
Now, the taylor series is going to be (at first order in h/R):
a(R) is actually the constant acceleration at sea level
and
Therefore:
Consider that the error in this expresion is quadratic in (h/R), and to consider quadratic correctiosn you must expand the taylor series to the next power:
Answer:
Radius of orbit = 3.992 × m
Altitude of Satellite =33541.9× m
Explanation:
Formula for gravitational force for a satellite of mass m moving in an orbit of radius r around a planet of mass M is given by;
Where G = Gravitational constant = 6.67408 × 10-11
We are given
F= 800 N
m = 320 Kg
M = 5.972 × Kg
G = 6.67408 × 10-11
We have to find radius r =?
putting values in formula;
==> 800 =6.67408 ×× 320 × 5.972 ×
/
==> 800= 39.8576 × × 320 /
==> 800 = 12754.43 × /
==> = 12754.43 ×
/800
==> =15.94 ×
==> r = 3.992 × m
==> r = 39920× m
This is the distance of satellite from center of earth. To find altitude we need distance from surface of earth. So we will subtract radius of earth from this number to find altitude.
Radius of earth =6378.1 km = 6378.1 × m
Altitude = 39920× - 6378.1 ×