Answer:
The normal force will be "122.8 N".
Explanation:
The given values are:
Weight,
W = 100 N
Force,
F = 40 N
Angle,
θ = 35.0°
As we know,
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
⇒ 
When the comet is closest to the Sun,
it has its maximum kinetic energy
and minimum gravitational potential energy. When the comet is far away from the Sun, it has maximum gravitational potential energy and minimal kinetic energy. It's faster when it's close because the Sun's gravity is pulling the comet closer. The opposite for when it gets farther away
We are given the equation:
<span>x = 11t^2
</span>
We use that equation to calculate for the distance traveled.
For (a)
At t=2.20 sec,
x =53.24 meters
At t=2.95 sec,
x =95.73 meters
Velocity = (95.73 meters - 53.24<span> meters) / (2.95 s - 2.20 s ) = 56.65 m/s
</span>For (b)
At t=2.20 sec,
x =53.24 meters
At t=2.40 sec,
x =63.36 meters
Velocity = (63.36 meters - 53.24<span> meters) / (2.40 s - 2.20 s ) = 50.6 m/s</span>
Efficiency η of a Carnot engine is defined to be:
<span>η = 1 - Tc / Th = (Th - Tc) / Th </span>
<span>where </span>
<span>Tc is the absolute temperature of the cold reservoir, and </span>
<span>Th is the absolute temperature of the hot reservoir. </span>
<span>In this case, given is η=22% and Th - Tc = 75K </span>
<span>Notice that although temperature difference is given in °C it has same numerical value in Kelvins because magnitude of the degree Celsius is exactly equal to that of the Kelvin (the difference between two scales is only in their starting points). </span>
<span>Th = (Th - Tc) / η </span>
<span>Th = 75 / 0.22 = 341 K (rounded to closest number) </span>
<span>Tc = Th - 75 = 266 K </span>
<span>Lower temperature is Tc = 266 K </span>
<span>Higher temperature is Th = 341 K</span>
