How does a steam engine do work?

A body moving with an acceleration 2 m/s?then what is the change in velocity in 4sec.

enot [183]

Answer:

As Per Provided Information

Moving body has 2m/s² acceleration

Time taken by body is 4 second

We are asked to find the 'change in velocity' ( ∆V) by the body.

Formula Used here

$\boxed{\bf{\Delta \: V \: = acceleration \: \times time \:}}$

Substituting the given value

$\sf\longrightarrow\Delta\:V \: = 2 \times 4 \\ \\ \\ \sf\longrightarrow\Delta\:V \: =8m {s}^{ - 1}$

Therefore,

Change in velocity is 8 m/s

7 0

1 year ago

Which of the following is a common feature among the four inner planets?

denpristay [2]

rocky surface

(outer plants are made of gas)

6 0

2 years ago

a 6.7kg object moves with a velocity of 8 m/s. whats its kinetic energy?(A)26.8J(B)214.4J(C)167.5J(D)53.6J

Ne4ueva [31]

The answer in (B)214.4J

I hope this helped have a nice day!

6 0

2 years ago

Read 2 more answers

Select the correct answer from the drop-down menu. A box contains shirts in two different colors and two different sizes. The nu

yKpoI14uk [10]

Answer:

P( red | large shirt ) ≠ P( large shirt)

P( Blue | large shirt ) = P( blue shirt)

P( shirt is medium and blue ) ≠ P( medium shirt)

P( large shirt | red shirt ) ≠ P( red shirt)

Explanation:

P( red | large shirt ) = 42/77 = 0.5454 : P( large shirt)= 77/165 = 0.467

P( red | large shirt ) ≠ P( large shirt)

P( Blue | large shirt ) = 35/77 = 0.4545 : P( blue shirt)= 75/165 = 0.4545

P( Blue | large shirt ) = P( blue shirt)

P( Shirt is medium and blue ) = 40/77 = 0.2424 : P( medium shirt)= 88/165 = 0.5333

P( shirt is medium and blue ) ≠ P( medium shirt)

P( large shirt | red shirt) = 42/90 = 0.4667 : P( red shirt)= 90/165 = 0.5454

P( large shirt | red shirt ) ≠ P( red shirt)

7 0

2 years ago

Read 2 more answers

A 1.89 kg object on a frictionless horizontal track is attached to the end of a horizontal spring whose force constant is 4.77 N

Maksim231197 [3]

Answer:

Magnitude F(t)=26.6 N

Direction: -x

Explanation:

Given data

Spring constant K=4.77 N/m

Mass m=1.89 kg

Displace A=5.56m

Time t=3.96s

To find

Magnitude of force F

Solution

The angular frequency is given as

$w=\sqrt{\frac{K}{m} } \\w=\sqrt{\frac{4.77N/m}{1.89kg} }\\w=1.59rad/s$

Force on object is

$F(t)=-mAw^{2}Cos(wt)$

Substitute given values

So

$F(t)=-(1.89kg)(5.56m)(1.59rad/s)^{2}Cos(1.59*3.96)\\F(t)=-26.6N$

So

Magnitude F(t)=26.6 N

Direction: -x

4 0

2 years ago