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Mariana [72]
4 years ago
6

How does a steam engine do work?

Physics
1 answer:
Viktor [21]4 years ago
4 0
Steam enters a cylinder—- A
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If a 2000 kg car is at rest and a 500 N force is applied to it. What acceleration will it experience?
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Net Force = mass * acceleration.
Therefore, Acceleration = Net force / mass
A=2000/500
A=4 m/s^2
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P1: Explain in detail - How can the motion of an object that is already moving change? (What are the different ways a moving obj
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Inertia: tendency of an object to resist changes in its velocity. An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force.

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4 years ago
A stone is dropped from the roof of a high building. a second stone is dropped 1.50 s later. how far apart are the stones when t
Aleksandr [31]

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distance = 0.5*9.8*1.33^2 = 8.67 meters

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3 years ago
The total number of protons and neutrons in an atom's nucleus is called 5
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3 years ago
A circuit with a lagging 0.7 pf delivers 1500 watts and 2100VA. What amount of vars must be added to bring the pf to 0.85
kvasek [131]

Answer:

\mathtt{Q_{sh} = 600.75 \ vars}

Explanation:

Given that:

A circuit with a lagging 0.7 pf delivers 1500 watts and 2100VA

Here:

the initial power factor  i.e cos θ₁ = 0.7 lag

θ₁ = cos⁻¹ (0.7)

θ₁ = 45.573°

Active power P = 1500 watts

Apparent power S = 2100 VA

What amount of vars must be added to bring the pf to 0.85

i.e the required power factor here is cos θ₂ = 0.85 lag

θ₂ =  cos⁻¹   (0.85)

θ₂ = 31.788°

However; the initial reactive power Q_1 = P×tanθ₁

the initial reactive power Q_1 = 1500 × tan(45.573)

the initial reactive power Q_1 = 1500 × 1.0202

the initial reactive power Q_1 =  1530.3 vars

The amount of vars that must therefore be added to bring the pf to 0.85

can be calculated as:

Q_{sh} = P( tan \theta_1 - tan \theta_2)

Q_{sh} = 1500( tan \ 45.573 - tan \ 31.788)

Q_{sh} = 1500( 1.0202 - 0.6197)

Q_{sh} = 1500( 0.4005)

\mathtt{Q_{sh} = 600.75 \ vars}

3 0
3 years ago
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