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stich3 [128]
3 years ago
10

Harry and ron set up this experiment with a glider, whose mass they have measured to be 565 g, and seven washers hanging from th

e string. if each washer has a mass of 12 g, what is the acceleration of the system, in m/s2
Physics
1 answer:
svetlana [45]3 years ago
5 0
Let's call m=565~g=0.565~kg the mass of the glider and m_w=7\cdot12~g =84~g=0.084~kg the total mass of the seven washers hanging from the string. 
The net force on the system is given by the weight of the hanging washers:
F_{net} = m_w g
For Newton's second law, this net force is equal to the product between the total mass of the system (which is m+m_w) and the acceleration a:
F_{net}=(m+m_w)a
So, if we equalize the two equations, we get
m_w g = (m+m_w)a
and from this we can find the acceleration:
a= \frac{m_w g}{(m+m_w)} = \frac{0.084~kg \cdot 9.81~m/s^2}{(0.565~kg+0.084~kg)}=1.27~m/s^2
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