This is the Lewis structure for NH3.
Answer:
The Bohr atomic model did not make correct predictions of large- sized atoms and provided sufficient information only for smaller atoms.
Answer: ΔH°f of gaseous nitrogen monoxide is 148.0 kJ/mol
Explanation:
The balanced chemical reaction is,

The expression for enthalpy change is,
![\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_f%28product%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_f%28reactant%29%5D)
![\Delta H_{rxn}=[(n_{NO_2}\times \Delta H_f_{NO_2})]-[(n_{O_2}\times \Delta H_f_{O_2})+(n_{NO}\times \Delta H_f_{NO})]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%28n_%7BNO_2%7D%5Ctimes%20%5CDelta%20H_f_%7BNO_2%7D%29%5D-%5B%28n_%7BO_2%7D%5Ctimes%20%5CDelta%20H_f_%7BO_2%7D%29%2B%28n_%7BNO%7D%5Ctimes%20%5CDelta%20H_f_%7BNO%7D%29%5D)
where,
n = number of moles
(as heat of formation of substances in their standard state is zero
Now put all the given values in this expression, we get
![-114.14=[(1\times 33.90)]-[(\frac{1}{2}\times 0)+(1\times \Delta H_f{NO})]](https://tex.z-dn.net/?f=-114.14%3D%5B%281%5Ctimes%2033.90%29%5D-%5B%28%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200%29%2B%281%5Ctimes%20%5CDelta%20H_f%7BNO%7D%29%5D)

Therefore, ΔH°f of gaseous nitrogen monoxide is 148.0 kJ/mol
Answer:
First box: 3
Second box: 4
Third box: 3
Fourth box: 4
Explanation:
I tried out various numbers, but got 3 and 4 because:
3PbI4 + 4CrCl3 -----> 3PbCl4 + 4CrI3
Each term cancels put.
3Pb --> 3Pb
4Cr --> 4Cr
and so forth...
Hope this helps!