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According to the chemical equation, the reaction ratio between O2 and CO2 is 2:1, which mean for every 2 moles of O2 reacted there is 1 mole of CO2 formed.
Use the molar mass and mass of O2 to find out the moles of O2: moles of O2 = mass of O2/molar mass of O2 = 8.94g/32.00g/mol = 0.2794 mole. Therefore, the moles of CO2 that formed is 0.2794moles/2 = 0.1397 mole
Use the moles and molar mass CO2 to find out the mass of CO2:
Mass of CO2 = moles of CO2 * molar mass of CO2 = 0.1397 mole * .44.01g/mole = 6.15 g.
So the answer is B 6.15g.
a. 0.137
b. 0.0274
c. 1.5892 g
d. 0.1781
e. 5.6992 g
<h3>Further explanation</h3>
Given
Reaction
2 C4H10 + 13O2 -------> 8CO2 + 10H2O
2.46 g of water
Required
moles and mass
Solution
a. moles of water :
2.46 g : 18 g/mol = 0.137
b. moles of butane :
= 2/10 x mol water
= 2/10 x 0.137
= 0.0274
c. mass of butane :
= 0.0274 x 58 g/mol
= 1.5892 g
d. moles of oxygen :
= 13/2 x mol butane
= 13/2 x 0.0274
= 0.1781
e. mass of oxygen :
= 0.1781 x 32 g/mol
= 5.6992 g
Answer:
Explanation:
a) for 1.000 g X: 0.1621 g Y
ratio of mass of element Y = 2.100g : 0.1621g
= 1 : 0.07
b) 1.000 g X: 0.7391 g Y
ratio of mass of element Y = 2.100g : 0.7391g
= 1: 0.35 , = 20:7
c) 1.000 g X: 0.2579 g Y
ratio of mass of element Y = 2.100g : 0.2579g
= 1 : 0.12
d) 1.000 g X: 0.2376 g Y
ratio of mass of element Y = 2.100g : 0.2376g
= 1: 0.11
e) 1.000 g X: 0.2733 g Y
ratio of mass of element Y = 2.100g : 0.2733g
= 1 : 0.13
From the values obtained , the closest that is in compliance with the law f multiple proportions is option B
Answer: D
Explanation:
im not sure if its wright or not