Answer:
The period of oscillation is 1.33 sec.
Explanation:
Given that,
Mass = 275.0 g
Suppose value of spring constant is 6.2 N/m.
We need to calculate the angular frequency
Using formula of angular frequency
![\omega=\sqrt{\dfrac{k}{m}}](https://tex.z-dn.net/?f=%5Comega%3D%5Csqrt%7B%5Cdfrac%7Bk%7D%7Bm%7D%7D)
Where, m = mass
k = spring constant
Put the value into the formula
![\omega=\sqrt{\dfrac{6.2}{275.0\times10^{-3}}}](https://tex.z-dn.net/?f=%5Comega%3D%5Csqrt%7B%5Cdfrac%7B6.2%7D%7B275.0%5Ctimes10%5E%7B-3%7D%7D%7D)
![\omega=4.74\ rad/s](https://tex.z-dn.net/?f=%5Comega%3D4.74%5C%20rad%2Fs)
We need to calculate the period of oscillation,
Using formula of time period
![T=\dfrac{2\pi}{\omega}](https://tex.z-dn.net/?f=T%3D%5Cdfrac%7B2%5Cpi%7D%7B%5Comega%7D)
Put the value into the formula
![T=\dfrac{2\pi}{4.74}](https://tex.z-dn.net/?f=T%3D%5Cdfrac%7B2%5Cpi%7D%7B4.74%7D)
![T=1.33\ sec](https://tex.z-dn.net/?f=T%3D1.33%5C%20sec)
Hence, The period of oscillation is 1.33 sec.
It would be d and c hoped i helped!
Since you didn't provide how tall the Monument was, I took the liberty to find it and it is 555 feet tall. So to convert to meters we must divide 555 by 3.28 or multiply it by 0.3048 (this is the method I used).
555 x 0.3048 = 169.164 meters
Answer:
Explanation:
At constant pressure , work done by gas = P x ΔV where P is pressure and ΔV is change in volume
ΔV = 9.2 - 5.6 = 3.6 L
3.6 L = 3.6 x 10⁻³ m³
ΔV = 3.6 x 10⁻³ m³
P = 3.7 x 10³ Pa
So work done
= 3.7 x 10³ x 3.6 x 10⁻³ J
= 13.32 J .
( c ) is the answer , because work is done by the gas so it will be positive.