All categories

2 years ago

2c+02=2CO2. The moles of co2 produced when 0.25 moles of O2 react is?

Chemistry

1 answer:

Sophie [7]2 years ago

7 0

<h3>Answer:</h3>

$\displaystyle 0.5 \ mol \ CO_2$

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Moles
Compounds

Stoichiometry

Using Dimensional Analysis
Analyzing Reactions RxN

<h3>Explanation:</h3>

Step 1: Define

[RxN - Balanced] 2C + O₂ → 2CO₂

[Given] 0.25 moles O₂

[Solve] moles CO₂

Step 2: Identify Conversions

[RxN] 1 mol O₂ → 2 mol CO₂

Step 3: Stoichiometry

[DA] Set up: $\displaystyle 0.25 \ moles \ O_2(\frac{2 \ mol \ CO_2}{1 \ mol \ O_2})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 0.5 \ mol \ CO_2$

You might be interested in

Please help me it's a emergency!!!!!

PilotLPTM [1.2K]

Answer:

probably a space probe because the sun is too hot for anything else to go on the sun

Explanation:

8 0

3 years ago

For the following reaction, KcKc = 255 at 1000 KK.

bonufazy [111]

Answer :

The equilibrium concentration of CO is, 0.016 M

The equilibrium concentration of Cl₂ is, 0.034 M

The equilibrium concentration of COCl₂ is, 0.139 M

Explanation :

The given chemical reaction is:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial conc. 0.1550 0.173 0

At eqm. (0.1550-x) (0.173-x) x

As we are given:

$K_c=255$

The expression for equilibrium constant is:

$K_c=\frac{[COCl_2]}{[CO][Cl_2]}$

Now put all the given values in this expression, we get:

$255=\frac{(x)}{(0.1550-x)\times (0.173-x)}$

x = 0.139 and x = 0.193

We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.139

The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M

The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M

The equilibrium concentration of COCl₂ = x = 0.139 M

5 0

3 years ago

What happens to the temperature and density of the material between points B and C?

makvit [3.9K]

Answer:

Temperature decreases and density increases

Explanation:

Let us remember that density of a material increases as the temperature of the material decreases. So the cooler a material becomes, the denser it becomes also.

Between points B and C, the material rapidly cools down and the temperature decreases accordingly. This ultimately results in an increase in density since cooler materials are denser than hot materials.

7 0

3 years ago

What is the endpoint of a titration?Select one:When there is no acid and all base.When the amount of acid and base are equal.Whe

user100 [1]

Answer:

The correct option is: When the amount of acid and base are equal

Explanation:

Titration is an analytic method that is used to determine the concentration of an unknown solution, called titrand.

In this method, standard solution of known concentration, called titrant, is taken in the burette and added drop-wise to the titrand solution in the flask, until the endpoint is reached.

In case of an acid-base titration, a pH indicator is used, which changes the color of the solution when the endpoint is reached.

The endpoint indicates the equivalence point of an acid-base titration, where the concentration of the acid and base is equal.

Therefore, the correct option is: When the amount of acid and base are equal

3 0

3 years ago

Find [cu2+] in a solution saturated with cu4(oh)6(so4) if [oh − ] is fixed at 2.3 ✕ 10−6 m. note that cu4(oh)6(so4) gives 1 mol

ki77a [65]

$Cu_4(OH)_6(SO_4)$

You have OH- conc = 2.3 ✕ 10−6 m
From the formula, you can observe the ratio of Cu2+ to OH- is 4 : 6 = 2:3

So, for 2.3 ✕ 10−6 m OH-
[Cu2+] = $\frac{2}{3} \times 2.3 \times 10^{-6}$

$= 1.53 \times 10^{-6} 
$

6 0

4 years ago

2c+02=2CO2. The moles of co2 produced when 0.25 moles of O2 react is?​

2c+02=2CO2. The moles of co2 produced when 0.25 moles of O2 react is?