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Ira Lisetskai [31]
4 years ago
6

he balanced net ionic equation for precipitation of CaCO 3 when aqueous solutions of Na 2CO 3 and CaCl 2 are mixed is ________.

2Na (aq) CO32- (aq) Na2CO3 (aq) 2Na (aq) 2Cl- (aq) 2NaCl (aq) Na (aq) Cl- (aq) NaCl (aq) Ca (aq) CO32- (aq) CaCO3 (s) Na2CO3 (aq) CaCl2 (aq) 2NaCl (aq) CaCO3 (s)
Chemistry
1 answer:
ale4655 [162]4 years ago
6 0

Answer:

Net ionic equation: Ca^{2+}(aq.)+CO_{3}^{2-}(aq.)\rightarrow CaCO_{3}(s)

Explanation:

Reaction between Na_{2}CO_{3} and CaCl_{2} is an example of double decomposition reaction where each cations and anions of each salt exchange their partners during reaction to form CaCO_{3} and NaCl

CaCO_{3} is an insoluble salt. Hence precipitation of CaCO_{3} has been observed.

Molecular equation: Na_{2}CO_{3}(aq.)+CaCl_{2}(aq.)\rightarrow 2NaCl(aq.)+CaCO_{3}(s)

Total ionic equation:

2Na^{+}(aq.)+CO_{3}^{2-}(aq.)+Ca^{2+}(aq.)+2Cl^{-}(aq.)\rightarrow CaCO_{3}(s)+2Na^{+}(aq.)+2Cl^{-}(aq.)

Here Na^{+} and Na^{+} are spectator ions. Therefore they are eliminated from both side of total ionic equation to get net ionic equation.

Net ionic equation: Ca^{2+}(aq.)+CO_{3}^{2-}(aq.)\rightarrow CaCO_{3}(s)

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Well for one the Oceans food chain starts with the sun and then microscopic organisms such as phytoplankton, and if they were destroyed the fish and other small creatures would eventually die off and then larger animals would too. Then that could lead to not much sea life, or sea food left for other people and animals

8 0
3 years ago
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PLEASE PLEASE HELP!
valentinak56 [21]

Answer: The number of grams of H_2 in 1620 mL is 1.44 g

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = 1620 ml = 1.62 L  (1L=1000ml)

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =273K

n=\frac{PV}{RT}

n=\frac{1atm\times 16.2L}{0.0821Latm/K mol\times 273K}=0.72moles

Mass of hydrogen =moles\times {\text {Molar mass}}=0.72mol\times 2g/mol=1.44g

The number of grams of H_2 in 1620 mL is 1.44 g

8 0
4 years ago
Methanol, ethanol, and n−propanol are three common alcohols. When 1.00 g of each of these alcohols is burned in air, heat is lib
Sergeeva-Olga [200]

Answer:

a) Heat of combustion of 1 g of methanol = -22.6 kJ = (-2.26 × 10) kJ

b) Heat of combustion of 1 g of ethanol = -29.7 kJ = (-2.97 × 10) kJ

c) Heat of combustion of 1 g of propanol = -33.5 kJ = (-3.35 × 10) kJ

Explanation:

a) The equation for the combustion of methanol is given as

CH₃OH + (3/2)O₂ → CO₂ + 2H₂O

The standard heat of combustion of methanol is given as -726 kJ/mol from literature.

But, 1 g of methanol will have the heat of combustion of the number of moles of methanol contained in 1 g of methanol.

Number of moles = (mass)/(molar mass)

Molar mass of (CH₃OH) = 32.04 g/mol

Number of moles = (1/32.04) = 0.03121 moles

1 mole of methanol has a heat of combustion of -726 kJ

0.03121 mole of methanol will have a heat of combustion of (0.03121 × -726) = -22.6 kJ

b) The equation for the combustion of ethanol is given as

C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O

The standard heat of combustion of ethanol is given as -1367.6 kJ/mol from literature.

But, 1 g of ethanol will have the heat of combustion of the number of moles of ethanol contained in 1 g of ethanol.

Number of moles = (mass)/(molar mass)

Molar mass of (C₂H₅OH) = 46.07 g/mol

Number of moles = (1/46.07) = 0.0217 moles

1 mole of ethanol has a heat of combustion of -1367.6 kJ

0.0217 mole of ethanol will have a heat of combustion of (0.03121 × -1367.6) = -29.7 kJ

c) The equation for the combustion of propanol is given as

C₃H₇OH + (9/2)O₂ → 3CO₂ + 4H₂O

The standard heat of combustion of propanol is given as -2020 kJ/mol from literature.

But, 1 g of propanol will have the heat of combustion of the number of moles of propanol contained in 1 g of propanol.

Number of moles = (mass)/(molar mass)

Molar mass of (C₃H₇OH) = 60.09 g/mol

Number of moles = (1/60.09) = 0.0166 moles

1 mole of propanol has a heat of combustion of -2020 kJ

0.0166 mole of propanol will have a heat of combustion of (0.0166 × -2020) = -33.5 kJ

Hope this Helps!!!

5 0
3 years ago
The major group of organic chemicals that has double the number of hydrogen atoms as carbon or oxygen atoms, signified by the ch
gulaghasi [49]

The major group of organic chemicals that has double the number of hydrogen atoms as carbon or oxygen atoms [chemical formula (ch2o)n] is carbohydrates.

<h3>What are carbohydrates?</h3>

Carbohydrates are biological macromolecules that function as macronutrients by providing energy, which are composed of simple carbon-based molecules linked by glycosidic bonds.

In conclusion, the major group of organic chemicals that has double the number of hydrogen atoms as carbon or oxygen atoms [chemical formula (ch2o)n] is carbohydrates.

Learn more about carbohydrates here:

brainly.com/question/336775

#SPJ1

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Why does burning coal produce more heat energy than burning paper
Vlad1618 [11]
Because it contain very high carbon contend as compare to paper 
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