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ivann1987 [24]
3 years ago
6

Elias serves a volleyball at a velocity of 16 m/s. The mass of the volleyball is 0.27 kg. What is the height of the volleyball a

bove the gym floor when its total mechanical energy is 41.70 J? Round to the nearest tenth. m
Chemistry
1 answer:
yulyashka [42]3 years ago
5 0

Answer:

2,7m

Explanation:

Total mechanical energy is the sum of kinetic energy plus potential energy.

kinetic energy can be expressed like K=\frac{m.v^{2} }{2} and potential energy like U=m.g.h Where m is the mass, v is the velocity, g is the gravity on the earth surface (9,8m/s^2) and h is the height we want to know, so:

Total mechanical energy =  K=\frac{m.v^{2} }{2} + U=m.g.h

But Total mechanical energy = 41,71J = 41,71 kg.m^2/s^2

rearranging: h=\frac{E-(\frac{mv^{2} }{2} )}{m.g}

replacing: h=\frac{41.70J-(\frac{0,27kgx(16m/s)^{2} }{2}) }{0.27kgx9.8m/s^{2} } = 2,7m

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<h3>You will pay $ 30876800</h3>

We'll begin by calculating the mass in ounce (oz) of a cube foot (ft³) of gold. This can be obtained as follow:

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Density of gold = 19298 oz/ft³

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