Without enzymes the nutrients in your food would go to waste which leads to a poor digestion and malnutrition. It’s because enzymes break down the nutrients which use it for energy
Answer:
a. 5.77L
b. 700mmHg
c. 395K
Explanation:
Using PV = nRT we can solve these problems where:
P is pressure of the gas in atm (1atm = 760mmHg)
V is volume in liters
n are moles of the gas
R is gas constant: 0.082atmL/molK
T is asbolute temperature in K
a. PV = nRT
V = nRT/P
P = 773mmHg*(1atm/760mmHg) = 1.017atm
T = 25°C+273 = 298K
V = 0.240mol*0.082atmL/molK*298K / 1.017atm
V = 5.77L
b. PV = nRT
P = nRT/V
P = 0.0947mol*0.082atmL/molK*309K/0.635L
P = 0.9216atm * (760mmHg/1atm) = 700mmHg
c. PV = nRT
PV/nR = T
P = 727mmHg * (1atm / 760mmHg) = 0.9566atm
0.9566atm*13.3L/0.393mol*0.082atmL/molK = T
T = 395K
Answer:
the specific heat of the unknown compound is 
Explanation:
Generally the change in temperature of water is evaluated as
Substituting 16.1°C for 
and 27.4°C for 
Generally the change in temperature of unknown compound is evaluated as
Substituting 27.4°C for and 94.3°C for 
Since there is an increase in temperature then heat is gained by water and this can be evaluated as
Substituting 179.1 g for m , 4.18 J/g.C for 
(specific heat of water)
Since there is a decrease in temperature then heat is lost by unknown compound and this can be evaluated as
By conservation of energy law
Heat lost = Heat gained
Substituting 306.9 g for 
, 8459.6J for 
Therefore 
HNO₃ + H₂S → S + NO + H₂<span>O
Assign Oxidation Number:
L.H.S R.H.S
N in HNO</span>₃ = +5 +2 = N in NO
S in H₂S = -2 0 = S in S
Write Half cell Reactions:
Reduction Reaction:
3e⁻ + HNO₃ → NO -------(1)
Oxidation Reaction:
H₂S → S + 2e⁻ -------(2)
Multiply eq. 1 with 2 and eq. 2 with 3 to balance electrons.
6e⁻ + 2 HNO₃ → 2 NO
3 H₂S → 3 S + 6e⁻
Cancel e⁻s,
______________________________
2 HNO₃ + 3 H₂S → 2 NO + 3 S + H₂O
Balance Oxygen Atoms by multiplying H₂O with 4, Hydrogen atoms will automatically get balance.
2 HNO₃ + 3 H₂S → 2 NO + 3 S + 4H₂O
Answer:
use coefficients and subscripts to determine how many atoms are in a compound. If there is no subscript or coefficient, assume it is 1. If there is a coefficient, multiply it with the subscripts. For counting cations and anions, determine first which is the anion and cation (anion = nonmetal, cation = metal), then count the number of that ion.
Example:
NaCl
one atom of Na, one atom of Cl. Since Na is a metal, it is a cation. Cl is a nonmetal, so it is an anion.
2CaCl2
2 atoms of Ca, 4 atoms of Cl. There are 2 cations, since Na is a metal, and 4 anions since Cl is a nonmetal
