Answer:
a. 8.96 m/s b. 1.81 m
Explanation:
Here is the complete question.
a) A long jumper leaves the ground at 45° above the horizontal and lands 8.2 m away.
What is her "takeoff" speed v
0
?
b) Now she is out on a hike and comes to the left bank of a river. There is no bridge and the right bank is 10.0 m away horizontally and 2.5 m, vertically below.
If she long jumps from the edge of the left bank at 45° with the speed calculated in part a), how long, or short, of the opposite bank will she land?
a. Since she lands 8.2 m away and leaves at an angle of 45 above the horizontal, this is a case of projectile motion. We calculate the takeoff speed v₀ from R = v₀²sin2θ/g. where R = range = 8.2 m.
So, v₀ = √gR/sin2θ = √9.8 × 8.2/sin(2×45) = √80.36/sin90 = √80.36 = 8.96 m/s.
b. We use R = v₀²sin2θ/g to calculate how long or short of the opposite bank she will land. With v₀ = 8.96 m/s and θ = 45
R = 8.96²sin(2 × 45)/9.8 = 80.2816/9.8 = 8.192 m.
So she land 8.192 m away from her bank. The distance away from the opposite bank she lands is 10 - 8.192 m = 1.808 m ≅ 1.81 m
Answer:
Explanation:
wavelength, λ = 3.4 m
wavelength, λ' = 3.3 m
Speed, v = 340 m/s
f = v / λ = 340 / 3.4 = 100 Hz
f' = v / λ' = 340 / 3.3 = 103.03 Hz
Frequency of beat, n = f' - f = 103.03 - 100 = 3.03 Hz
The acceleration of the sled will be 1.30 m/s². Force is defined as the product of mass and acceleration.
<h3>What is force?</h3>
Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
Given data;
m(mass of sled)=8 kg
Θ is the inclination of force= 50°
Force of friction,f=2.4 N.
The applied force at the given angle is resolved into the two-component as;
The net vertical force is zero;
From Newton's second law the net force as;
Hence, the acceleration of the sled will be 1.30 m/s².
To learn more about the force refer to the link;
brainly.com/question/26115859
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Image #3 good luck!!!!!!!!!!!