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RUDIKE [14]
3 years ago
5

Explain how a CO2 cartridge powers the dragster you will be building. A good website to use is How Stuff Works. (howstuffworks.c

om) Write a good paragraph or two to explain your answer in complete sentences.
Engineering
2 answers:
Sonbull [250]3 years ago
7 0
Co2 cartridges are pressed
andrezito [222]3 years ago
5 0

Answer

C02 cartridges are compressed.

Explanation:

The C02 Cartridge will be used to power our dragsters by the compression inside of the bottle. Since C02 is a compressed gas inside of a small container, The pressure when released my provide enough force to move the dragster at high speeds. An example of this would be like an air soft gun. some air soft guns are used by small C02 Cartridges, which let out a strong burst of compressed C02, which fires the projectiles at very high speeds.

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Which term defines the amount of mechanical work an engine can do per unit of heat energy it uses?
skad [1K]

Answer:

d

Explanation:

is the because that's the amount of work in making machine can do producing heat

7 0
4 years ago
Question 8 of 10
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3 years ago
Danny enjoys studying transportation networks and systems. Which field of engineering should he pursue?
andre [41]

Answer:

Civil Engineering.

Explanation:

Civil Engineering is a field of engineering study that deals with professional practising in designing and developing infrastructures such as transport system and networks, buildings, etc.

<u>Civil engineering is regarded as the second--oldest form of engineering studies in the field of engineering.</u>

<u>A person who studies civil engineering is able to design and develop major projects in transportations system such as road construction, bridges, airports, tunnels, etc.</u>

So, Danny, who is interested in studying transporation networks and system should opt for studying civil engineering.

8 0
3 years ago
A solid shaft and a hollow shaft of the same material have same length and outer radius R. The inner radius of the hollow shaft
alexandr402 [8]

Answer with Explanation:

By the equation or Torque we have

\frac{T}{I_{p}}=\frac{\tau }{r}=\frac{G\theta }{L}

where

T is the torque applied on the shaft

I_{p} is the polar moment of inertia of the shaft

\tau is the shear stress developed at a distance 'r' from the center of the shaft

\theta is the angle of twist of the shaft

'G' is the modulus of rigidity of the shaft

We know that for solid shaft I_{p}=\frac{\pi R^4}{2}

For a hollow shaft I_{p}=\frac{\pi (R_o^4-R_i^4)}{2}

Since the two shafts are subjected to same torque from the relation of Torque we have

1) For solid shaft

\frac{2T}{\pi R^4}\times r=\tau _{solid}

2) For hollow shaft we have

\tau _{hollow}=\frac{2T}{\pi (R^4-0.7R^4)}\times r=\frac{2T}{\pi 0.76R^4}

Comparing the above 2 relations we see

\frac{\tau _{solid}}{\tau _{hollow}}=0.76

Similarly for angle of twist we can see

\frac{\theta _{solid}}{\theta _{hollow}}=\frac{\frac{LT}{I_{solid}}}{\frac{LT}{I_{hollow}}}=\frac{I_{hollow}}{I_{solid}}=1.316

Part b)

Strength of solid shaft = \tau _{max}=\frac{T\times R}{I_{solid}}

Weight of solid shaft =\rho \times \pi R^2\times L

Strength per unit weight of solid shaft = \frac{\tau _{max}}{W}=\frac{T\times R}{I_{solid}}\times \frac{1}{\rho \times \pi R^2\times L}=\frac{2T}{\rho \pi ^2R^5L}

Strength of hollow shaft = \tau '_{max}=\frac{T\times R}{I_{hollow}}

Weight of hollow shaft =\rho \times \pi (R^2-0.7R^2)\times L

Strength per unit weight of hollow shaft = \frac{\tau _{max}}{W}=\frac{T\times R}{I_{hollow}}\times \frac{1}{\rho \times \pi (R^2-0.7^2)\times L}=\frac{5.16T}{\rho \pi ^2R^5L}

Thus \frac{Strength/Weight _{hollow}}{Strength/Weight _{Solid}}=5.16

3 0
3 years ago
Water exerts little pressure on a building so it has no implications on foundation design.
777dan777 [17]

Fact

Explanation:

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7 0
3 years ago
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