Answer:
Energy produce in one year =20.49 x 10¹⁶ J/year
Explanation:
Given that
Plant produce 6.50 × 10⁸ J/s of energy.
It produce 6.50 × 10⁸ J in 1 s.
We know that
1 year = 365 days
1 days = 24 hr
1 hr = 3600 s
1 year = 365 x 24 x 3600 s
1 year = 31536000 s
So energy produce in 1 year = 31536000 x 6.50 × 10⁸ J/year
Energy produce in one year = 204984 x 10¹² J/year
Energy produce in one year =20.49 x 10¹⁶ J/year
Answer:
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Explanation:
Answer:
option B is correct. Fracture will definitely not occur
Explanation:
The formula for fracture toughness is given by;
K_ic = σY√πa
Where,
σ is the applied stress
Y is the dimensionless parameter
a is the crack length.
Let's make σ the subject
So,
σ = [K_ic/Y√πa]
Plugging in the relevant values;
σ = [50/(1.1√π*(0.5 x 10^(-3))]
σ = 1147 MPa
Thus, the material can withstand a stress of 1147 MPa
So, if tensile stress of 1000 MPa is applied, fracture will not occur because the material can withstand a higher stress of 1147 MPa before it fractures. So option B is correct.
78950W the answer
Explanation:
A 75- kw, 3-, Y- connected, 50-Hz 440- V cylindrical synchronous motor operates at rated condition with 0.8 p.f leading. the motor efficiency excluding field and stator losses, is 95%and X=2.5ohms. calculate the mechanical power developed, the Armature current, back e.m.f, power angle and maximum or pull out torque of the motor
A 75- kw, 3-, Y- connected, 50-Hz 440- V cylindrical synchronous motor operates at rated condition with 0.8 p.f leading. the motor efficiency excluding field and stator losses, is 95%and X=2.5ohms. calculate the mechanical power developed, the Armature current, back e.m.f, power angle and maximum or pull out torque of the motor
