Answer:
Check the explanation
Explanation:
Question 1.
The secondary current of 250/5 amps CT when 300 amps(rated current of transmission line ) flow in TL is
(5/250 ) X 300 = 6 amps
Question 2
The correct answer to this second question is yes, when Over current relay coil will operate and relay contacts gets close, if the pickup value( Ip) of relay is set as 6 amps in relay. ( because primary current of TL is 1.2 times of CT primary)
Question 3
Tap Block figure (Fig 1) is not available/uploaded in your question.
Answer:
<em>a) 4.51 lbf-s^2/ft</em>
<em>b) 65.8 kg</em>
<em>c) 645 N</em>
<em>d) 23.8 lb</em>
<em>e) 65.8 kg</em>
<em></em>
Explanation:
Weight of the man on Earth = 145 lb
a) Mass in slug is...
32.174 pound = 1 slug
145 pound =
slug
= 145/32.174 = <em>4.51 lbf-s^2/ft</em>
b) Mass in kg is...
2.205 pounds = 1 kg
145 pounds =
kg
= 145/2.205 = <em>65.8 kg</em>
c) Weight in Newton = mg
where
m is mass in kg
g is acceleration due to gravity on Earth = 9.81 m/s^2
Weight in Newton = 65.8 x 9.81 = <em>645 N</em>
d) If on the moon with acceleration due to gravity of 5.30 ft/s^2,
1 m/s^2 = 3.2808 ft/s^2
m/s^2 = 5.30 ft/s^2
= 5.30/3.2808 = 1.6155 m/s^2
weight in Newton = mg = 65.8 x 1.6155 = 106
weight in pounds = 106/4.448 = <em>23.8 lb</em>
e) The mass of the man does not change on the moon. It will therefore have the same value as his mass here on Earth
mass on the moon = <em>65.8 kg</em>
Answer: Create lessons learned at the end of the project.
Explanation:
Lessons learned are the experiences that are gotten from a project which should be taken into account for the future projects. Lesson learned are created at the end of the project.
The main objective of the lessons learned is that they show both the positive experience and the negative experience of a project and this will help the future projects that will be undertaken.
Answer:
6.5 × 10¹⁵/ cm³
Explanation:
Thinking process:
The relation ![N_{o} = N_{i} * \frac{E_{f}-E_{i} }{KT}](https://tex.z-dn.net/?f=N_%7Bo%7D%20%3D%20N_%7Bi%7D%20%2A%20%5Cfrac%7BE_%7Bf%7D-E_%7Bi%7D%20%20%7D%7BKT%7D)
With the expression Ef - Ei = 0.36 × 1.6 × 10⁻¹⁹
and ni = 1.5 × 10¹⁰
Temperature, T = 300 K
K = 1.38 × 10⁻²³
This generates N₀ = 1.654 × 10¹⁶ per cube
Now, there are 10¹⁶ per cubic centimeter
Hence, ![N_{d} = 1.65*10^{16} - 10^{16} \\ = 6.5 * 10^{15} per cm cube](https://tex.z-dn.net/?f=N_%7Bd%7D%20%20%3D%201.65%2A10%5E%7B16%7D%20%20-%2010%5E%7B16%7D%20%5C%5C%20%20%20%20%20%20%20%20%20%20%20%3D%206.5%20%2A%2010%5E%7B15%7D%20per%20cm%20cube)
Answer:
B- extreme fit, close fit, adjustable fit
Explanation:
A human-fit design typically involves the process of manufacturing or producing products (tools) that are easy to use by the end users. Therefore, human-fit designs mainly deals with creating ideas that makes the use of a particular product comfortable and convenient for the end users.
The design for human-fit strategies include; extreme fit, close fit and adjustable fit.
Hence, when the aforementioned strategies are properly integrated into a design process, it helps to ensure the ease of use of products and guarantees comfort for the end users.