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2 years ago

Water is unique because

Chemistry

1 answer:

wolverine [178]2 years ago

7 0

Answer:

b. It exists in three different states at normal conditions in the Earth's atmosphere

Explanation:=

Snow, rain and water vapour can exist at normal conditions in the Earth's atmosphere.

a. is wrong. Only hydrogen and helium can escape Earth's atmosphere in significant amounts.

c. is wrong. The molecules of every substance are in motion even when it is solid.

d. is wrong. Other substances can form from a wide range of chemical processes.

e. is wrong. All substances expand when they become a gas.

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Rutherford proposed that atoms have positive nuclei. Which statement correctly describes the nucleus of an atom?

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I think that The answer is B

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3 years ago

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The decomposition of copper(II) nitrate on heating is endothermic reaction. 2Cu(NO3)2(s) → 2C10(s) + 4NO2(g) + O2(g) Calculate t

Basile [38]

Answer:

The enthalpy change for the given reaction is 424 kJ.

Explanation:

$2Cu(NO_3)_2(s)\rightarrow 2CuO(s) + 4NO_2(g) + O_2(g),\Delta H_{rxn}=?$

We have :

Enthalpy changes of formation of following s:

$\Delta H_{f,Cu(NO_3)_2}=-302.9 kJ/mol$

$\Delta H_{f,CuO}=-157.3 kJ/mol$

$\Delta H_{f,NO_2}= 33.2 kJ/mol$

$\Delta H_{f,O_2}= 0 kJ/mol$ (standard state)

$\Delta H_{rxn}=\sum [\Delta H_f(product)]-\sum [\Delta H_f(reactant)]$

The equation for the enthalpy change of the given reaction is:

$\Delta H_{rxn}$ =

$=(2 mol\times \Delta H_{f,CuO}+4\times \Delta H_{f,NO_2}+1 mol\times \Delta H_{f,O_2})-(2mol\times \Delta H_{f,Cu(NO_3)_2})$

$\Delta H_{rxn}$ =

$(2mol\times (-157.3 kJ/mol)+4\times 33.2 kJ/mol=1 mol\times 0 kJ/mol)-(2 mol\times (-302.9 kJ/mol)$

$\Delta H_{rxn}=424 kJ$

The enthalpy change for the given reaction is 424 kJ.

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3 years ago

How is condensation explained by the Kinetic Molecular Theory? Cooling reduces particle motion, resulting in coalescence by attr

lara31 [8.8K]

Temperature means, in this context, movement.

Condensation can be explained by the reduction of temperature of the system. This effect make possible the cohesion forces increases. In other words, the result is coalescence by attractive forces.

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Calculate the number of grams of solute in 500.0 mL of 0.189 M KOH.

KIM [24]

Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

Solution : Given,

Volume of solution = 500 ml

Molarity of KOH solution = 0.189 M

Molar mass of KOH = 56 g/mole

Formula used :

$Molarity=\frac{\text{Mass of KOH}\times 1000}{\text{Molar mass of KOH}\times \text{Volume of solution in ml}}$

Now put all the given values in this formula, we get the mass of solute KOH.

$0.189M=\frac{\text{Mass of KOH}\times 1000}{(56g/mole)\times (500ml)}$

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