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IrinaK [193]
3 years ago
12

A sample of neon gas occupies a volume of 2.8L at 1.8 atm. What would its volume be at 1.2 atm?

Chemistry
1 answer:
puteri [66]3 years ago
3 0

Answer:

4.2 L

Explanation:

Use Boyle's Law and rearrange formula.

- Hope this helps! Please let me know if you need further explanation.

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The atomic radius decreases across a period from left to right and increases down a given group. The atoms with the largest atomic radii are located in group l and at the bottom of groups. Moving from left to right across a period, electrons are added one at a time to the outer energy shell. Hope this helps!
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In reaction a, each sodium atom gives one electron to a chlorine atom in reaction be an isotope of oxygen decays to form an isot
aalyn [17]

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Exthermal heat, i think

Explanation:

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Would magnesium prefer to lose or gain electrons
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8 0
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Methanol and butanol are alcohols. Alcohols have the same_______________ as alkanes and the __________ identifies the compound a
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Answer:

Methanol and butanol are alcohols. Alcohols have the same_______________ as alkanes and the __________ identifies the compound as an alcohol.

Explanation:

Alcohols belong to a group of organic compounds which contain -OH group as the functional group.

So alcohols have the same carbon -hydrogen bonds as alkanes and the        -OH functional group identifies the compound as an alcohol.

8 0
3 years ago
The ka of hypochlorous acid (hclo) is 3.0 ⋅ 10−8 at 25.0 °c. calculate the ph of a 0.0375m hypochlorous acid solution.
Scrat [10]
We can set up an ICE table for the reaction:                      
                      HClO          H+     ClO-
Initial              0.0375       0        0
Change         -x               +x      +x
Equilibrium    0.0375-x     x        x

We calculate [H+] from Ka:     
     Ka = 3.0x10^-8 = [H+][ClO-]/[HClO] = (x)(x)/(0.0375-x)

Approximating that x is negligible compared to 0.0375 simplifies the equation to         
     3.0x10^-8 = (x)(x)/0.0375     
     3.0x10^-8 = x2/0.0375     
     x2 = (3.0x10^-8)(0.0375) = 1.125x10^-9     
     x = sqrt(1.125x10^-9) = 0.0000335 = 3.35x10^-5 = [H+]
in which 0.0000335 is indeed negligible compared to 0.0375.

We can now calculate pH:     
     pH = -log [H+] = - log (3.35 x 10^-5) = 4.47
6 0
4 years ago
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