Answer:
Rutherford's experiment, also known as

supports the existence of neutrons and the nucleus.
Explanation:
In the above diagram, Rutherford was trying to explain his contributions using thin foils of gold and other metals as targets for alpha particles from a radioactive source.
He observed that the majority of particles penetrated the foil either undeflected or with only a slight deflection. But, every now and then an alpha particle was scattered(or deflected) at a large angle..
According to Rutherford, most of the atoms must be empty space. This explains why the majority of alpha particles passed through through the gold foil with little or no deflection. The atoms positive charges, Rutherford proposed are all concentrated in the Nucleus, <em>which</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>dense</em><em> </em><em>central</em><em> </em><em>core</em><em> </em><em>withi</em><em>n</em><em> </em><em>the</em><em> </em><em>atom</em><em>. </em>
Whenever an alpha particle came close to a nucleus in the scattering experiment, it experienced a large repulsive force and therefore a large deflection. Moreover, an alpha particle coming towards a nucleus would be completely repelled and its direction would be reversed. The positively charged particles in the Nucleus are called Protons.
I <em>hope</em><em> </em><em>you</em><em> </em><em>find</em><em> </em><em>this</em><em> </em><em>useful</em><em>.</em><em>.</em><em>. </em><em>Have</em><em> </em><em>a</em><em> </em><em>lovely</em><em> </em><em>day</em><em>. </em>
First, we have to calculate the number of moles of H2SO4 in the solution:
V=60 mL = 0.06 L
c=5.85 mol/L
n=V×c=0.06×5.85=0.351 mol
Then we need to find the molar mass of H2SO4:
2×Ar(H) + Ar(S) + 4×Ar(O) =
=2 + 32 + 64 = 98 g/mol
Finally, we need to find the mass of H2SO4:
m=0.351 × 98 = 34.398 g
Quantitative is anything that is relating to a number value. Think “quantity”
Example:
1. There are 5 ml of water
2. There are 3 beakers
3. It takes 30 minutes for the reaction
Qualitative is about characteristics that can be described
Example
1. The liquid is green
2. The solution turned into a gas
3. Bubbles were produced
H3PO4 + H2O <--> H3O+ + H2PO4- Ka1= ([H3O+][H2PO4-])/[H3PO4])
H2PO4- + H2O <--> H3O+ + HPO4^2- Ka2= ([H3O+][HPO4^2-])/[H2PO4-])
HPO4^2- + H2O <--> H3O+ PO4^3- Ka3= ([H3O+][PO4^3-])/[HPO4^2-])
Ka1 >> Ka2 = almost all the H3O+ is formed in the first step.
Ka3 will only happen under very basic conditions.
Answer:
(a) The true solution is homogeneous mixture which cannot be separated by the process of filtration. A true solution is said to be stable and transparent. Three beakers are taken in which 100mL water is added and are labelled as A,B,C.
Explanation: