Answer:
what is this language i dont know about it
can you please send me in English
Answer:
The rate constant of the reaction at 125˚ is
.
Explanation:
The Arrhenius equation is a simple equation that describes the dependent relationship between temperature and the rate constant of a chemical reaction. The Arrhenius equation is written mathematically as


where
is the rate constant,
represents the activation energy of the chemical reaction,
is the gas constant,
is the temperature, and
is the frequency factor.
The frequency factor,
, is a constant that is derived experimentally and numerically that describes the frequency of molecular collisions and their orientation which varies slightly with temperature but this can be assumed to be constant across a small range of temperatures.
Consider that the rate constant be
at an initial temperature
and the rate constant
at a final temperature
, thus


Given that
,
,
,
, and
, therefore,
Answer:
Explanation:
Lead Monoxide: PbO
Nitric Acid: HNO3
PbO + 2 HNO3 ---> Pb(NO3)2 + H2O
Answer:
dark brown with a hint of purple
have a good day :)
Explanation:
The grams of ethane present in a sample containing 0.4271 mole is 12.84 g
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation
Mole = mass / molar mass
With the above formula, we can obtain the mass of ethane. Details below
<h3>How to determine the mass of ethane</h3>
The following data were obtained from the question:
- Mole of ethane = 0.4271 mole
- Molar mass of ethane = 30.067 g/mol
- Mass of ethane =?
The mass of ethane present in the sample can be obtained as follow:
Mole = mass / molar mass
Cross multiply
Mass = mole × molar mass
Mass of ethane = 0.4271 × 30.067
Mass of ethane = 12.84 g
Learn more about mole:
brainly.com/question/13314627
#SPJ1