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Serjik [45]
3 years ago
14

You place air in a sealed can at standard temperature and pressure (stp). you heat it to four times its absolute temperature (k)

while leaving the volume constant. what happens to the pressure?
Chemistry
1 answer:
pochemuha3 years ago
4 0
By Gayle-Lussac's law, the pressure and temperature of a fixed volume and amount of gas is directly proportional.
Thus,

P/T = constant

So if the temperature is increased four times, the pressure is also increased four times.
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A reversible reaction is one where A) there are large changes in the net free energy from substrate to product. B) there is litt
laila [671]

Answer:

A reversible reaction is one where <u><em>B) there is little change in the net free energy between substrate and product.</em></u>

Explanation:

A reversible reaction is one that reagents are transformed into products and at the same time products are transformed into reagents. That is to say that as the products appear in the reaction, they can react with each other by regenerating the reagents again. It is represented by a double arrow, indicating that the reaction can be carried out both in one direction and the other way around.

At the start of the reaction, there is a large amount of reagents. As time goes by, that amount decreases and speed too.

On the other hand, at the beginning of the reaction there are no products. As the reaction happens, the products are being formed and their speed will increase to match the speed of the reagents. When the rates of products and reagents are equal and constant, it is possible to say that the reaction is in chemical equilibrium. At this point, both reactions continue to happen, but the total concentrations of reagents and products no longer change.

The Gibbs free enthalpy or free energy of a system is a measure of the amount of usable energy (energy that a job can perform) in that system.

When a reaction system is in chemical equilibrium, it is in the lowest possible energy state (it has the lowest possible free energy). If a reaction is not in equilibrium, it will move spontaneously towards it because that allows it to reach a state of lower and more stable energy. Then when the reaction moves towards equilibrium, the free energy of the system decreases more and more.

Finally, <u><em>a reversible reaction is one where B) there is little change in the net free energy between substrate and product.</em></u>

4 0
3 years ago
Compare which element would have larger first ionization energy: an alkali metal in Period 2 or an alkali metal in Period 4?
maria [59]

Answer:

An alkali metal present in period 2 have larger first ionization energy.

Explanation:

Ionization energy:

The amount of energy required to remove the electron from the atom is called ionization energy.

Trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.  Thus alkali metal present in period 2 have larger ionization energy because of more nuclear attraction as compared to the alkali metal present in period 4.

6 0
3 years ago
The atomic NUMBER tells which information below. Check all that apply.
Pie

Answer:

1 the number of electrons

3 0
3 years ago
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Write the expression for the equilibrium constant Kp for the following reaction. (Enclose pressures in parentheses and do NOT wr
Liono4ka [1.6K]

Answer and Explanation:

For the following balanced reaction:

PCl₅(g) ↔ PCl₃(g) + Cl₂(g)

We can see that all reactants and products are gases, so it is an homogeneous equilibrium. The expression for the equilibrium constant Kp can be written from the partial pressures (P) of reactants and products as follows:

Kp=\frac{(P PCl_{3})(P Cl_{2})}{(P PCl_{5})}

Where PPCl₃ is the partial pressure of PCl₃ (reactant), PCl₂ is the partial pressure of Cl₂ (reactant) and PPCl₅ is the partial pressure of PCl₅ (product).

6 0
3 years ago
Explain why need modifications about temperature and keep pressure atom
Yuri [45]

Answer:

The pressure law states that for a constant volume of gas in a sealed container the temperature of the gas is directly proportional to its pressure. ... This means that they have more collisions with each other and the sides of the container and hence the pressure is increased.

7 0
3 years ago
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