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ASHA 777 [7]
2 years ago
12

Calculate the energy required to heat 406.0mg of cyclohexane from 33.5°C to 38.9°C . Assume the specific heat capacity of cycloh

exane under these conditions is 1.85·J·g^−1K^−1 . Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
N76 [4]2 years ago
6 0

Answer:

Q = 4.056 J

Explanation:

  • Q = m<em>C</em>ΔT

∴ m = 406.0 mg = 0.406 g

∴ <em>C </em>= 1.85 J/g.K

∴ T1 = 33.5°C ≅ 306.5 K

∴ T2 = 38.9°C = 311.9 K

⇒ ΔT = 311.9 - 306.5 = 5.4 K

⇒ Q = (0.406 g)(1.85 J/gK)(5.4 K)

⇒ Q = 4.056 J

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Given the equation 2mg(s) + o2(g) → 2mgo(s) + 72.3 kj, how much heat is involved in the production of 5.0 mol of mgo? question 2
Rudik [331]
The heat is involved   in the  production of 5.0 mol of MgO  is   180 Kj

               calculation

2 Mg (s)   +O2 → 2 MgO

From  the  equation  above two  moles    of MgO  is used  therefore   

72.3   is for   2   moles

that is   72.3  kj =  2moles
                  ?      = 5  moles 

by  cross  multiplication

= 72.3  kj × 5/2     = 180  Kj  
    

7 0
3 years ago
What causes a rearrangement of atoms?
AURORKA [14]

Answer:

When a atom is unstable (It wants to gain or lose a valence electron)

4 0
3 years ago
Which number represents where the substance has a definite shape and a definite volume?
Len [333]

Answer:

The Letter I

Explanation:

There are two flat horizontal lines. Those are phase changes. I is the solid state before the first phase change where the substance goes from a solid to a liquid.

So the answer is I

4 0
2 years ago
Strontium has a atomic number of 38 and a mass number of 88 how many neutrons are in one atom
dem82 [27]
Atomic number=number of protons (and electrons, but that doesn't matter in this answer)
Atomic mass=number of protons+number of neutrons
Atomic mass=atomic number+number of neutrons
Atomic mass-atomic number=number of neutrons
88-38=number of neutrons
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6 0
2 years ago
Read 2 more answers
A 20.7167 g sample of impure magnesium carbonate was heated to complete decomposition according to the equation mgco3(s) → mgo(s
marishachu [46]

The mass of impure MgCO_{3} is 20.7167 g. The decomposition reaction is as follows:

MgCO_{3}(s)\rightarrow MgO(s)+CO_{2}(g)

Here, 1 mole of MgCO_{3} gives 1 mole of MgO.

Molar mass of MgCO_{3}  and MgO is 84.31 g/mol and 40.3044 g/mol respectively.

Converting number of moles in terms of mass,

n=\frac{m}{M}

Here, M is molar mass.

Since, n_{MgCO_{3}}=n_{MgO}

Thus, \frac{m_{MgCO_{3}}}{M_{MgCO_{3}}}=\frac{m_{MgO}}{M_{MgO}}

On putting the values,

\frac{m_{MgCO_{3}}}{84.31}=\frac{m_{MgO}}{40.3044}

Rearranging,

m_{MgO}=\frac{m_{MgCO_{3}}}{84.31}\times 40.3044

Or,

m_{MgCO_{3}}=\frac{m_{MgO}}{0.4780}...... (1)

Let the mass of impurity be M_{I}  and mass of impure MgCO_{3} is 20.7167 g thus,

M_{MgCO_{3}}=(20.7167-M_{I})g...... (2)

Also, mass of impure MgO is 16.8817 g thus,

M_{MgO}=(16.8817-M_{I})g...... (3)

On comparing equations (2) and (3),

M_{MgO}=M_{MgCO_{3}}-3.835

Putting the value of M_{MgO} in equation (1),

m_{MgCO_{3}}=\frac{M_{MgCO_{3}}-3.835}{0.4780}

Or,

0.4780 M_{MgCO_{3}}=M_{MgCO_{3}}-3.835

Or,

M_{MgCO_{3}}-0.4780M_{MgCO_{3}}=3.835

Or,

0.522 M_{MgCO_{3}}=3.835

Or,

M_{MgCO_{3}}=\frac{3.835}{0.522}=7.35 g

Thus, magnesium carbonate present in the original sample is 7.35 g.


5 0
3 years ago
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