Hi. I would like to know why one side of an island can get more rain (more rain forms), while the other gets less.
2 answers:
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Answer:
16 minutes
Explanation:
This is an example of a class of problems in which two quantities start with different initial values and change at different rates. In such problems, the rates of change are generally ones that cause the values to converge.
The question usually asks when the values will be the same. The generic answer is, "when the difference in rates makes up the difference in initial values."
Here the tanks differ in initial fill height by 12 -8 = 4 ft. The rates of change differ by 0.5 -0.25 = 0.25 ft/min. The more filled tank is draining faster (important), so the fill heights will converge after ...
(4 ft)/(0.25 ft/min) = 16 min
The level in the two tanks will be the same after 16 minutes.
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<em>Additional comment</em>
The oil levels at that time will be 4 ft.
You can write two equations for height:
y = 12 -0.5x . . . . . . . height in feet after x minutes (tank A)
y = 8 -0.25x . . . . . . height in feet after x minutes (tank B)
These will be equal when ...
y = y
12 -0.5x = 8 -0.25x
4 = 0.25x . . . . . . . . . . add 0.5x -8
16 = x . . . . . . . . . . . . multiply by 4 . . . . time to equal height
The graph shows when the tanks will have equal heights and when they will be drained.
Answer:
hello your question has some missing part attached below is the complete question
answer : steady state temperature = 419.713k ≈ 218.7⁰c
Time required to reach a junction ≈ 5 secs
Explanation:
The detailed solution of the given problem is attached below but the solution to the subsequent problem from which the question you asked is referenced to( problem 1 ), is not attached because it was not part of the question you asked
Answer:
Check the explanation
Explanation:
#include <iostream>
using namespace std;
void insert(int* arr, int* size, int value, int position){
if(position<0 || position>=*size){
cout<<"position is greater than size of the array"<<endl;
return ;
}
*size = *size + 1 ;
for(int i=*size;i>position;i--){
arr[i] = arr[i-1];
}
arr[position] = value ;
}
void print(int arr[], int size){
for(int i=0;i<size;i++){
cout<< arr[i] <<" ";
}
cout<<" "<<endl;
}
void remove(int* arr, int* size, int position){
* size = * size - 1 ;
for(int i=position;i<*size;i++){
arr[i] = arr[i+1];
}
}
int count(int arr[], int size, int target){
int total = 0 ;
for(int i=0;i<size;i++){
if(arr[i] == target)
total += 1 ;
}
return total ;
}
int main()
{
int size;
cout<<"Enter the initial size of the array:";
cin>>size;
int arr[size],val;
cout<<"Enter the values to fill the array:"<<endl;
for(int i=0;i<size;i++){
cin>>val;
arr[i] = val ;
}
int choice = 5,value,position,target ;
do{
cout<<"Make a selection:"<<endl;
cout<<"1) Insert"<<endl;
cout<<"2) Remove"<<endl;
cout<<"3) Count"<<endl;
cout<<"4) Print"<<endl;
cout<<"5) Exit"<<endl;
cout<<"Choice:";
cin>>choice;
switch(choice){
case 1:
cout << "Enter the value:";
cin>>value;
cout << "Enter the position:";
cin>>position;
insert(arr,&size,value,position);
break;
case 2:
cout << "Enter the position:";
cin>>position;
remove(arr,&size,position);
break;
case 3:
cout<<"Enter the target value:";
cin>>target;
cout <<"The number of times "<<target<<" occured in your array is:" <<count(arr,size,target)<<endl;
break;
case 4:
print(arr,size);
break;
case 5:
cout <<"Thank you..."<<endl;
break;
default:
cout << "Invalid choice..."<<endl;
}
}while(choice!=5);
return 0;
}
Kindly check the attached images below for the code output.
