Answer:
(i) Oxidizing Agent: NO2 / Reducing Agent NH3-
(ii) Oxidizing Agent AgNO3 / Reducing Agent Zn
Explanation:
(i) 8NH3( g) + 6NO2( g) => 7N2( g) + 12H2O( l)
In this reaction, both two reactants contain nitrogen with a different oxidation number and produce only one product which contains nitrogen with a unique oxidation state. So, nitrogen is oxidized and reduced in the same reaction.
Nitrogen Undergoes a change in oxidation state from 4+ in NO2 to 0 in N2. It is reduced because it gains electrons (decrease its oxidation state). NO2 is the oxidizing agent (electron acceptor).
Nitrogen Changes from an oxidation state of 3- in NH3 to 0 in N2. It is oxidized because it loses electrons (increase its oxidation state). NH3 is the reducing agent (electron donor)
(ii) Zn(s) +AgNO3(aq) => Zn(NO3)2(aq) + Ag(s)
Ag changes oxidation state from 1+ to 0 in Ag(s).
Ag is reduced because it gains electrons and for this reason and AgNO3 is the oxidizing agent (electron acceptor)
Zn Changes from an oxidation state of 0 in Zn(s) to 2+ in Zn(NO3)2. It is oxidized and for this reason Zn is the reducing agent (electron donor).
Balanced equation:
Zn(s) +2AgNO3(aq) => Zn(NO3)2(aq) + 2Ag(s)
Answer:
Details are below
Explanation:
A Compound is made of number of atom of element, that have a specific ratio.
Below are the details of elements and the number of its atoms:
1) NaOH
Element : #of atoms
Na 1
O 1
H 1
__________________
Total 3
---------------------------------
2) HNO₃
Element : #of atoms
H 1
N 1
O 3
___________________
Total 4
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3) Li₂O
Element : #of atoms
Li 2
O 1
__________________
Total 3
------------------------------------
4) Li₂SO₄
Element : #of atoms
Li 2
S 1
O 4
____________________
Total 7
------------------------------------------
5) NH₄Cl
Element : #of atoms
N 1
Cl 1
H 4
____________________
Total 6
------------------------------------------
6) CaClO₃
Element : #of atoms
Ca 1
Cl 1
O 3
____________________
Total 5
------------------------------------------
7) H₂COCH₂
Element : #of atoms
C 2
H 4
O 1
____________________
Total 7
------------------------------------------
8) Mg(OH)₂
Element : #of atoms
Mg 1
H 2
O 2
____________________
Total 5
------------------------------------------
9) Al(OH)₃
Element : #of atoms
Al 1
H 3
O 3
____________________
Total 7
------------------------------------------
10) NH₄C₂H₃O₂
Element : #of atoms
N 1
H 7
C 2
O 2
____________________
Total 12
------------------------------------------
11) NaC₂H₃O₂
Element : #of atoms
Na 1
H 3
C 2
O 2
____________________
Total 8
------------------------------------------
12) (NH₄)₃ PO₄
Element : #of atoms
N 3
H 12
P 1
O 4
____________________
Total 20
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When Cr dissolves in 1 M H₂Cr₂O₇
Cr(s) ⇄ Cr³⁺ + 3 e⁻
Cr₂O₇²⁻ + 14 H⁺ + 6 e⁻ ⇄ 2 Cr³⁺ + 7 H₂O
by multiplying the first equation by 2 and add the 2 equations;
The balanced redox reaction will be:
2 Cr(s) + Cr₂O₇²⁻(aq) + 14 H⁺(aq) → 4 Cr³⁺(aq) + 7 H₂O(l)
It’s c because beryllium is light