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3 years ago

10.

Physics

1 answer:

tatuchka [14]3 years ago

6 0

Answer:

Explanation:

Earth Mars Jupiter Saturn,Uranus, naptune

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A car traveling at 22m/s is in an accident, and the 81 kg driver is brought to a stop in 1.4 s by in inflating airbag. What forc

larisa86 [58]

Here, F = m * a
F = m * v/t
Here, m = 81 Kg
v = 22 m/s
t = 1,4 s

Substitute their values,
F = 81 * 22/1.4
F = 81 * 15.71
F = 1273 N
So, Closest value from your options is 1300 N

In short, Your Answer would be Option B

Hope this helps!

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4 years ago

When a compound is broken down in the chemical reaction, its atoms are

Makovka662 [10]

A. used to form new compound

3 0

3 years ago

Read 2 more answers

A muon has a rest mass energy of 105.7 MeV, and it decays into an electron and a massless particle. If all the lost mass is conv

sergeinik [125]

Answer:

The electron’s velocity is 0.9999 c m/s.

Explanation:

Given that,

Rest mass energy of muon = 105.7 MeV

We know the rest mass of electron = 0.511 Mev

We need to calculate the value of γ

Using formula of energy

$K_{rel}=(\gamma-1)mc^2$

$\dfrac{K_{rel}}{mc^2}=\gamma-1$

Put the value into the formula

$\gamma=\dfrac{105.7}{0.511}+1$

$\gamma=208$

We need to calculate the electron’s velocity

Using formula of velocity

$\gamma=\dfrac{1}{\sqrt{1-(\dfrac{v}{c})^2}}$

$\gamma^2=\dfrac{1}{1-\dfrac{v^2}{c^2}}$

$\gamma^2-\gamma^2\times\dfrac{v^2}{c^2}=1$

$v^2=\dfrac{1-\gamma^2}{-\gamma^2}\times c^2$

Put the value into the formula

$v^2=\dfrac{1-(208)^2}{-208^2}\times c^2$

$v=c\sqrt{\dfrac{1-(208)^2}{-208^2}}$

$v=0.9999 c\ m/s$

Hence, The electron’s velocity is 0.9999 c m/s.

6 0

3 years ago

A 2.35 kg ball is attached to a ceiling by a3.53 m long string. The height of the room is5.03 m .The acceleration of gravity is

Studentka2010 [4]

Answer:-81.29 J

Explanation:

Given

mass of ball $m=2.35 kg$

Length of string $L=3.53 m$

height of Room $h=5.03 m$

Gravitational Potential Energy is given by

$P.E.=mgh$

where h=distance between datum and object

here Reference is ceiling

therefore $h=-3.53 m$

Potential Energy of ball w.r.t ceiling

$P.E.=2.35\times 9.8\times (-3.53)=-81.29 J$

i.e. 81.29 J of Energy is required to lift a ball of mass 2.35 kg to the ceiling

3 0

3 years ago

You hold a small metal ball of mass a height above the floor. You let go, and the ball falls to the floor. Choose the origin of

baherus [9]

Answer:

yᵢ = h

vᵢᵧ = 0

Explanation:

Let initial velocity = u

final velocity = v

height = h

acceleration due to gravity = g

Therefore fro equation of motion,

$v^{2}=u^{2}+2gh$

Here initial velocity is zero.

Hence, $v^{2}=2gh$

$v = \sqrt{2gh}$

but since it points downward and you positive is taken in the up direction

$v = -\sqrt{2gh}$

5 0

4 years ago