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3 years ago

Calculate the momentum of a 10kg bowling ball rolling at 2 m/s.

Physics

1 answer:

Helen [10]3 years ago

5 0

Answer:

20 kg. m/s

Explanation:

p = mv

m = 10 kg

v = 2 m/s

p = 10 × 2

p = 20 kg m/s

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A rock has a mass of 3.1 kg. What is its weight on earth

Masteriza [31]

Answer:

W = 30.38 N

Explanation:

Given that,

Mass of a rock, m = 3.1 kg

We need to find the weight of the rock on the surface of Earth. Weight of an object is given by :

W = mg

g is the acceleration due to gravity, g = 9.8 m/s²

W = 3.1 kg × 9.8 m/s²

= 30.38 N

So, the weight of the rock on the Earth is 30.38 N.

6 0

2 years ago

Write the importance of international bureau of weights and measurement.

Taya2010 [7]

Answer:

The importance of international bureau of weights and measures are;

1. to bring unification of measurement system.

2. to establish and preserve fundamental international prototypes.

3. to verify national standards, etc.

8 0

3 years ago

A mass of 10 g of oxygen fill a weighted pistonâ€“cylinder device at 20 kPa and 110Â°C. The device is now cooled until the tempe

mezya [45]

Answer:

The change of the volume of the device during this cooling is $14.3\times10^{-3}\ m^3$

Explanation:

Given that,

Mass of oxygen = 10 g

Pressure = 20 kPa

Initial temperature = 110°C

Final temperature = 0°C

We need to calculate the change of the volume of the device during this cooling

Using formula of change volume

$\Delta V=V_{2}-V_{1}$

$\Delta V=\dfrac{mR}{P}(T_{2}-T_{1})$

Put the value into the formula

$\Delta V=\dfrac{0.3125\times0.0821}{2.0265\times10^{9}}(383-273)$

$\Delta V=14.297\ L$

$\Delta V=14.3\times10^{-3}\ m^3$

Hence, The change of the volume of the device during this cooling is $14.3\times10^{-3}\ m^3$

6 0

2 years ago

What is the gauge pressure in Pascals inside a honey droplet of a 0.1 cm diameter? Assume that air is surrounding this droplet a

Vikki [24]

Answer:

The gauge pressure in Pascals inside a honey droplet is 416 Pa

Explanation:

Given;

diameter of the honey droplet, D = 0.1 cm

radius of the honey droplet, R = 0.05 cm = 0.0005 m

surface tension of honey, γ = 0.052 N/m

Apply Laplace's law for a spherical membrane with two surfaces

Gauge pressure = P₁ - P₀ = 2 (2γ / r)

Where;

P₀ is the atmospheric pressure

Gauge pressure = 4γ / r

Gauge pressure = 4 (0.052) / (0.0005)

Gauge pressure = 416 Pa

Therefore, the gauge pressure in Pascals inside a honey droplet is 416 Pa

5 0

3 years ago

A potential energy function is given by U(x)=(3.00J)x+(1.00J/m2)x3. What is the force function F(x) (in newtons) that is associa

Anit [1.1K]

Answer:

$F(x)=-3 N - (3N)x^2$

Explanation:

The force is defined as the negative of the derivative of the potential energy:

$F=-\frac{dU}{dx}$

If we use the potential energy function given in this problem:

$U(x)=3.00 x + 1.00 x^3$

and we calculate the force, we get:

$F(x)=-\frac{d}{dx}(3x+x^3)=-3-3x^2$

So, the force is

$F(x)=-3 N - (3N)x^2$

5 0

2 years ago

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