Answer:
pH= 9.2
Explanation:
Henderson hasselbach equation
pKa= log Ka= log (4.9 x 10^-10)=9.3
![pH=Pka+log \frac{[A-]}{[HA]}](https://tex.z-dn.net/?f=pH%3DPka%2Blog%20%5Cfrac%7B%5BA-%5D%7D%7B%5BHA%5D%7D)
![pH=9.3+log \frac{[CN-]}{[HCN]}](https://tex.z-dn.net/?f=pH%3D9.3%2Blog%20%5Cfrac%7B%5BCN-%5D%7D%7B%5BHCN%5D%7D)
![pH=9.3+log \frac{[0.64 M]}{[0.83 M]}](https://tex.z-dn.net/?f=pH%3D9.3%2Blog%20%5Cfrac%7B%5B0.64%20M%5D%7D%7B%5B0.83%20M%5D%7D)
pH= 9.2
Oxygen gas expands in a container and when pressure is applied it liquifies and occupies a smaller volume
hope that helps <span />
Here we have to get the effect of addition of 0.25 moles of gas C on the mole fraction of gas A in a mixture of gas having constant pressure.
On addition of 0.25 moles of C gas, the mole fraction of gas A will be 
.
The partial pressure of gas A can be written as 
= 
×P (where is the mole fraction of gas A present in the mixture and P is the total pressure of the mixture.
The mole fraction of gas A in a mixture of gas A and C is = 
and 
respectively.
Thus on addition of 0.25 moles of C gas, the mole fraction of gas A will be .
Which is different from the initial state.
Answer:
Explanation:
As one moves down the vertical groupings of elements on the periodic table, it is evident that new shells are being added from top to down.
An atomic orbital is the region of space surrounding the nucleus where there is a high probability of finding an electron.
Down a group, the atomic radius increases as more shells are added to an atom.
Answer:
Measure the diameter of the circle using Ruler A and Ruler B.
Given that the actual diameter of the circle is 2.264 cm, classify the following statements that describe the diameter measurement of the circle according to the ruler.
Drag the appropriate items to their respective bins.
