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4 years ago

Identify 3 elements and 3 compounds. How are they the same? How are they different?

Chemistry

2 answers:

wlad13 [49]4 years ago

6 0

Answer:

The answer to your question is below

Explanation:

Elements Compounds

1.- Cu (Copper) NaCl (sodium chloride)

2.- Ag (Silver) HNO₃ (nitric acid)

3.- Al (aluminum) KOH (potassium hydroxide)

They are similar because that are composed by elements, they are different because elements are composed by only 1 element and compounds are composed by 2 or more elements.

Elements are simple and compounds are more complex structures.

Rudik [331]4 years ago

5 0

Answer: elements are gases: hydrogen (H2), nitrogen (N2), oxygen(O2), fluorine (F2), chlorine (Cl2), helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe) and radon (Rn).

Explanation:identify three elements and three compounds. ... They are similar because they are both pure substances but they are different because compounds have two or more different types of atoms while elements have the same exact type of atoms.

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VLD [36.1K]

Chemical reaction (dissociation) 1: C₂O₄H₂(aq) ⇄ C₂O₄H⁻(aq) + H⁺(aq).
Chemical reaction (dissociation) 2: C₂O₄H⁻(aq) ⇄ C₂O₄²⁻(aq) + H⁺(aq).
c(C₂O₄H⁻) = c(H⁺) = x.
c(C₂O₄H₂) = 0.0269 M.
pKa₁ = 1.23.
Ka₁ = 10∧(-1.23) = 0.059.
Ka₁ = c(C₂O₄H⁻) · c(H⁺) / c(C₂O₄H₂).
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3 0

3 years ago

You have just performed a laboratory activity where a lot of chemical waste was produced. all of the chemical wastes should be

Katyanochek1 [597]

D. Disposed of according to your teachers instructions

7 0

4 years ago

Read 2 more answers

A dilute solution of bromine in carbon tetrachloride behaves as an ideal-dilute solution. The vapour pressure of pure CCl4 is 33

ANEK [815]

Explanation:

The given data is as follows.

Vapour pressure of pure $CCl_{4}$ = 33.85 Torr

Temperature = 298 K

Mole fraction of $Br_{2}$ = 122.36 torr

Therefore, calculate the vapor pressure of $Br_{2}$ as follows.

Vapour pressure of $Br_{2}$ = mole fraction of $Br_{2}$ x K of $Br_{2}$

= 0.050 x 122.36 Torr

= 6.118 Torr

So, vapor pressure of $Br_{2}$ is 6.118 Torr .

Now, calculate the vapor pressure of carbon tetrachloride as follows.

Vapour pressure of $CCl_{4}$ = mole fraction of $CCl_{4}$ x Pressure of $CCl_{4}$

= (1 - 0.050) × 33.85 Torr

= 32.1575 Torr

So, vapor pressure of $CCl_{4}$ is 32.1575 Torr .

Hence, the total pressure will be as follows.

= 6.118 Torr + 32.1575 Torr

= 38.2755 Torr

Therefore, composition of $CCl_{4}$ = $\frac{32.1575 Torr}{38.2755 Torr}$

= 0.8405

Composition of $CCl_{4}$ is 0.8405 .

And, composition of $Br_{2}$ = $\frac{6.118 Torr}{38.2755 Torr}$

= 0.1598

Composition of $Br_{2}$ is 0.1598 .

6 0

4 years ago

If a piece of aluminum with a mass of 3.99 g and a temperature of 100.0 °C is dropped

Vinil7 [7]

Answer:

The final temperature of the system is 27.3°C.

Explanation:

Heat lost by aluminum = 3.99 × 0.91 × (100-T)

= 3.631 (100-T)

Heat gained by water = 10 × 4.184 × (T-21)

= 41.84 (T-21)

As,

Heat gained = Heat loss

or, 3.631(100-T) = 41.84(T-21)

or,363.1 - 3.631 T = 41.84 T - 878.64)

or, (41.84+ 3.631) T = 878.64 +363.1

or T= $\frac{1241.74}{45.47}$

or, T = 27.3°C

Hence the final temperature is 27.3°C.

8 0

3 years ago

Which is an example of an organism? A. an octopus B. sand granules C. water D. the colors of a feather

denpristay [2]

A. An octopus

An organism is an individual animal, plant, or single-celled life form.

The octopus is the only living thing listed so that is why it is the example of an organism

5 0

3 years ago