Answer:0.0704 kg
Explanation:
Given
initial Absolute pressure
=210+101.325=311.325



as the volume remains constant therefore



therefore Gauge pressure is 337.44-101.325=236.117 KPa
Initial mass 

Final mass 

Therefore
=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back
<span>Porous material has many spaces that can hold(store) groundwater.</span>
From the law of conservation of momentum
m1u1+ m2u2= m1v1+ m2v2
110*8+ 110*-10= 110*-10 + 110* v2
v2= 8 m/sec
Explanation:
It is given that,
Mass of the woman, m₁ = 52 kg
Angular velocity, 
Mass of disk, m₂ = 118 kg
Radius of the disk, r = 3.9 m
The moment of inertia of woman which is standing at the rim of a large disk is :


I₁ = 790.92 kg-m²
The moment of inertia of of the disk about an axis through its center is given by :


I₂ =897.39 kg-m²
Total moment of inertia of the system is given by :


I = 1688.31 kg-m²
The angular momentum of the system is :



So, the total angular momentum of the system is 4980.5 kg-m²/s. Hence, this is the required solution.