Answer:
E = 12640.78 N/C
Explanation:
In order to calculate the electric field you can use the Gaussian theorem.
Thus, you have:
ФE: electric flux trough the Gaussian surface
Q: net charge inside the Gaussian surface
εo: dielectric permittivity of vacuum = 8.85*10^-12 C^2/Nm^2
If you take the Gaussian surface as a spherical surface, with radius r, the electric field is parallel to the surface anywhere. Then, you have:
r can be taken as the distance in which you want to calculate the electric field, that is, 0.795m
Next, you replace the values of the parameters in the last expression, by taking into account that the net charge inside the Gaussian surface is:
Finally, you obtain for E:
hence, the electric field at 0.795m from the center of the spherical shell is 12640.78 N/C
<span>C.) A metalloid is used because it is a semiconductor and can become more conductive when more light shines on it.
Nonmetals do not conduct energy any way and you want the metalloid to be conductive so it can provide you with energy.
</span><span>C.) intermediate conductivity and a high melting point
</span>It conducts electricity fairly well.
Hope this helps.
5. D. 25-30
6. B. Accel 1 has a constant rate of acceleration; Accel 2 accelerates at different rates during the trip. Hope this helped.
Answer:
Explanation:
electric field = 2170 N/C
now the speed of the charge particle is given as
here we know that charge particle moves without any deviation
so we will have
now magnetic field in this region is given as
Now another charge particle enters the region with different speed and experience the force upwards
Air resistance is a type of friction.