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ANEK [815]
2 years ago
12

You normally drive on the freeway between San Diego and Los Angeles at an average speed of 105 km/h (65 mi/h), and the trip take

s 1 h and 50 min. On a Friday afternoon, however, heavy traffic slows you down and you drive the same distance at an average speed of only 70 km/h (43 mi/h). How much longer does the trip take?
Physics
1 answer:
valkas [14]2 years ago
3 0

Answer: 2 hr 45 min

Explanation:

Given

The average speed between San Diego and Los Angeles is 105\ kmph

time taken for this trip is  1\ hr\ 50\ min\ or\ \frac{11}{6}\ hr

Distance between San Diego and Los Angeles is

\Rightarrow d=105\times \dfrac{11}{6}\\\\\Rightarrow d=192.5\ km

For Friday afternoon, the average speed is  70\ km/h

time taken to complete the trip is

\Rightarrow t=\dfrac{192.5}{70}\\\\\Rightarrow t=2.75\ hr\ or\ 2\ hr\ 45\ min

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8.92 A 45.0 kg woman stands up in a 60.0 kg canoe 5.00 m long. She walks from a point 1.00 m from one end to a point I .00 m fro
omeli [17]

The distance that the canoe moves in this process is 1.29 meters.

We first have to find the center of mass

X = \frac{MsXs+McXc}{Mw+Mc} \\\\

Where

Ms = Woman's mass = 45

Mc = Canoe's mass = 60kg

Xs = position from left= 1 cm

Xc = position from left end of canoe's mass = 2.5cm

When we put these values into the equation we have:

X=\frac{45*1+60*2.5}{45+60} \\\\= 1.857\\

The center of gravity lies at the center of this boat. Therefore,

Xc = \frac{L}{2} \\\\L = 5 m long\\\\\frac{5}{2} =2.5

5.00 - 1. 00 = 4 meters

\frac{45*4+60*2.5}{45+60} = 3.14meters\\\\

To get the distance that is moved by this canoe

distance = 3.143-1.857

= 1.286

≈ 1.29 meters

The distance that the canoe moves in this process is 1.29 meters.

Read more on brainly.com/question/13198009?referrer=searchResults

6 0
2 years ago
An astronaut in a space craft looks out the window and sees an asteroid move pas a backward direction at 68 mph relative to the
Annette [7]

Answer: -194 mph

Explanation:

Taking into account the <u>Sun as the center </u>(origin, point zero) <u>of the reference system</u>, the velocity of the spacecraft relative to the Sun V_{R-S} is:

V_{R-S}=126mph  Note it is <u>positive</u> because the spacecraft is moving <u>away</u> from the Sun

Taking into account the <u>spacecraft as the center of another reference system</u>, the velocity of the asteroid relative to the spacecraft V_{A-R} is:

V_{A-R}=-68mph Note it is <u>negative</u> because the asteroid is moving<u> towards</u> the spacracft.

Now, the velocity of the asteroid relative to the Sun V_{A-S} is:

V_{A-S}=V_{A-R}-V_{R-S}

V_{A-S}=-68mph-126mph

Finally:

V_{A-S}=-194mph This is the velocity of the asteroid relative to the Sun and its negative sign indicates it is <u>moving towards the Sun</u>.

6 0
3 years ago
Please help me with 1,2,3,4,5,6
Trava [24]
I know that 4. Is wave 2 and 5. Is wave 3.
3 0
3 years ago
Joule’s law is a linear relationship, that is, the more heat you provide, the greater the temperature change. However, in the pr
Nitella [24]

Answer:

hydrogen bridge

Explanation:

Joule's relationship to heat and temperature is true for all materials where we assume that interatomic forces are linear, when atoms separate these forces decrease. There is a point where the separation between atoms is enough that thermal agitation can separate the molecules and there is a change of state, generally from solid to liquid and from liquid to vapor. When these changes of state are occurring all the energy supplied is used to break the links, so the temperature does not change.

In the specific case of water, there is a bond called a hydrogen bridge that breaks around 4ºC, therefore, at this temperature there is a deviation from the curve since this link is being broken, this does not lead to a change of macroscopic state.

For the other temperatures the water behaves like the other bodies.

7 0
3 years ago
A circuit has a voltage of 10 V and a current of 5 A. What must the resistance be?
azamat

Answer:

R=V/I

R= 2

Explanation:

R = 10V/5A

R = 2ohms

3 0
3 years ago
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