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ANEK [815]
3 years ago
12

You normally drive on the freeway between San Diego and Los Angeles at an average speed of 105 km/h (65 mi/h), and the trip take

s 1 h and 50 min. On a Friday afternoon, however, heavy traffic slows you down and you drive the same distance at an average speed of only 70 km/h (43 mi/h). How much longer does the trip take?
Physics
1 answer:
valkas [14]3 years ago
3 0

Answer: 2 hr 45 min

Explanation:

Given

The average speed between San Diego and Los Angeles is 105\ kmph

time taken for this trip is  1\ hr\ 50\ min\ or\ \frac{11}{6}\ hr

Distance between San Diego and Los Angeles is

\Rightarrow d=105\times \dfrac{11}{6}\\\\\Rightarrow d=192.5\ km

For Friday afternoon, the average speed is  70\ km/h

time taken to complete the trip is

\Rightarrow t=\dfrac{192.5}{70}\\\\\Rightarrow t=2.75\ hr\ or\ 2\ hr\ 45\ min

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The world’s supply of fossil fuels will _____.
Mekhanik [1.2K]

The world’s supply of fossil fuels will dwindle slowly until a replacement source is found that provides the same power.

bc some day we will actually run out of it and find sth that gives power

3 0
3 years ago
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Mashcka [7]

Answer:

Is it 11.8m high or 0.6?

The question is not clear

7 0
3 years ago
A technician wearing a brass bracelet enclosing area 0.00500 m2 places her hand in a solenoid whose magnetic field is 4.50 T dir
notka56 [123]

Answer:

39.375 A

Explanation:

To find the induced current, we use the relation

e = -ΔΦ/Δt, where

ΔΦ = change in magnetic flux of the bracelet

Δt = change in time, = 20 ms

Also, Φ = A.ΔB, such that

A = area of the bracelet, 0.005m²

ΔB = magnetic field strength of the bracelet = 1.35 - 4.5 = -3.15 T

ΔΦ = A.ΔB

ΔΦ = 0.005 * -3.15

ΔΦ = -.01575 wb

e = -ΔΦ/Δt

e = -0.01575 / 20*10^-3

e = 0.7875 V

From the question, the resistance of the bracelet is 0.02 ohm, so

From Ohms Law, I = V/R

I = 0.7875 / 0.02

I = 39.375 A

6 0
3 years ago
Assume that the average mass of each of the approximately 1 billion people in China is 55 kg.Assume that they all gather in one
Harman [31]

Answer: 5.9(10)^{-8} m

Explanation:

The equation to calculate the center of mass C_{M} of a particle system is:

C_{M}=\frac{m_{1}r_{1}+m_{1}r_{1}+...+m_{n}r_{n}}{m_{1}+m_{2}+...+m_{n}}

In this case we can arrange for one dimension, assuming the geometric center of the Earth and the ladder are on a line, and assuming original center of mass located at the Earth's geometric center:

C_{M}=\frac{m_{E}(0 m) + m_{p} r_{E-p}}{m_{E}+m_{p}}

Where:

m_{E}=5.9(10)^{24} kg is the mass of the Earth

m_{p}=55(10)^{9} kg is the mass of 1 billion people

r_{E}=6371000 m is the radius of the Earth

r_{E-p}=6371000 m- 2m=6370998 m is the distance between the center of the Earth and the position of the people (2 m above the Earth's surface)

C_{M}=\frac{m_{p}55(10)^{9} kg (6370998 m)}{5.9(10)^{24} kg+55(10)^{9} kg}

C_{M}=5.9(10)^{-8} m This is the displacement of Earth's center of mass from the original center.

8 0
3 years ago
A photon of light has a wavelength of about 600 nm (1nm = 1 x 10-9 m). What is the energy of this photon of light? Show all calc
bezimeni [28]
Wavelength = 600 nm = 600 × 10^(-9)
speed of light = c = 3 × 10^8
planck constant = h = 6.63 × 10^(-34)

energy of photon = hc/wavelength
 = 6.63 × 10^(-34) × 3 × 10^8/600 × 10^(-9)
 = 1.9 × 10^(-25)/6 × 10^(-7)
 = 0.31 × 10^(-16)
 = 3.1 × 10^(-17)
6 0
3 years ago
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