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aniked [119]
3 years ago
6

Where does the energy come from in a nuclear fission reaction?

Physics
1 answer:
poizon [28]3 years ago
4 0

Answer:ni

Explanation:

nnn

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What happens to the energy of a photon if the wavelength is doubled?.
Vladimir [108]

Answer:

Halving the wavelength doubles the frequency and, thus, doubles the energy of the incident photons. This doubles the energy given to each electron, nearly doubling its kinetic energy after it is free from the metal.

8 0
3 years ago
What information do you need to describe an object location
erastovalidia [21]
All you need to do is find what location you need and look it up and see if you get the right answer bruh
5 0
3 years ago
A 0.140 kg baseball is thrown horizontally with a velocity of 28.9 m/s. It is struck with a constant horizontal force that lasts
Viefleur [7K]

Answer:

4987N

Explanation:

Step 1:

Data obtained from the question include:

Mass (m) = 0.140 kg

Initial velocity (U) = 28.9 m/s

Time (t) = 1.85 ms = 1.85x10^-3s

Final velocity (V) = 37.0 m/s

Force (F) =?

Step 2:

Determination of the magnitude of the horizontal force applied. This can be obtained by applying the formula:

F = m(V + U) /t

F = 0.140(37+ 28.9) /1.85x10^-3

F = 9.226/1.85x10^-3

F = 4987N

Therefore, the magnitude of the horizontal force applied is 4987N

8 0
3 years ago
Compute the voltage drop along a 26-m length of household no. 14 copper wire (used in 15-A circuits). The wire has diameter 1.62
zepelin [54]

Answer:

V= 2.7 [v]

Explanation:

The value of the resistance is given by:

R=L*\frac{Rho}{A}\\\\where:\\R=resistance\\L=Lenght\\Rho=Resistivity\\A=Transversal -Area

so:

R=26m*\frac{(1.68*10^{-8}ohm*m)}{\pi *(\frac{1.628*10^{-3}m}{2})^2}\\R=0.21 Ohm

We can calulate the voltage dropped using the Ohm's law:

V=I*R\\V=13A*0.21Ohm=2.7V

8 0
3 years ago
If a bale of hay behind the target exerts a constant friction force, how much farther will your arrow burry itself into the hay
LenaWriter [7]

Answer:

The arrow will bury itself farther by 3S₁

Explanation:

<u />

lets assume; the Arrow shot by me has a speed twice the speed of the arrow fired by the younger shooter

Given that ; acceleration is constant , Frictional force is constant

                    A₂ =   A₁

Vf²₂ - Vi²₂ / 2s₂  = Vf₁² - Vi₁² / 2s₁ ---- ( 1 )

final velocities = 0

Initial velocities : Vi₂ = 2(Vi₁ )

Back to equation 1

0 - (2Vi₁ )² / 2s₂ =  0 - Vi₁² / 2s₁

hence :

s₂ = 4s₁

hence the Arrow shot by me will burry itself farther by :

s₂ - s₁ = 3s₁

<em>Note :  S1 = distance travelled by the arrow shot by the younger shooter</em>

8 0
3 years ago
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