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3 years ago

Why is it safe to watch an eclipse of the Moon but not an eclipse of the Sun

1 answer:

8 0

A solar eclipse occurs when the moon crosses in front of the Sun, blocking some or all of its rays. A lunar eclipse happens when the moon is directly behind the earth, blocking the moon from receiving light. The only light comes from the light on earth's reflected shadow.

You can look at a lunar eclipse because there is very little light or none at all. You can't look at a solar eclipse because you are looking directly at the sun unless it is complete. Before totality, only some of the Sun is blocked, causing your pupils dilate to let in more light. Since they do this, more of the Sun's rays can be let in to the eye, which effectively allows your eyes to burn.

Some doctors and eye care specialists say that after someone complains of blindness after looking at a solar eclipse unaided, they can see what the Sun and moon looked like at the time that they looked at it, as it is burned onto their retinas.

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HELP ME PLZ WILL GIVE BRAINLIEST ALSO 24 POINTS

Ludmilka [50]

Answer:

The highest vertical position is where your maximum potential energy lies. At the highest altitude point of course ! This is when the kinetic energy is only due to horizontal motion (since the vertical component reaches zero).

Explanation:

i looked it up ok

6 0

3 years ago

Greg and Tabitha are jogging together. At time t = 0, they are both traveling at a speed of 4 m/s, but Greg is 8 m ahead of Tabi

Ray Of Light [21]

Answer:

The answer to question is below

Explanation:

Data

t1 = 0

vo = 4 m/s

d = vot + $\frac{1}{2} at^{2}$

d = 4t + $\frac{1}{2} (1)t^{2} + 8$

$d = 8 + 4t + \frac{t^{2} }{2}$

$d = 4t + \frac{1}{2} (1.5)t^{2}$

$d = 4t + 0.75t^{2}$

$8 + 4t + \frac{t^{2} }{2}$ = $4t + 0.75t^{2}$

$4t + \frac{1}{2} t^{2} + 8 = 4t + \frac{1}{2} (1.5)t^{2} \\$

$0.75t^{2} - 0.5t^{2} = 8$

$0.25t^{2} = 8$

t² = 32

t = 5.66 s

d = 4(5.66) + 0.75(5.66)²

d = 22.64 + 24.02

d = 46.67 m

8 0

3 years ago

When you drop a ball it accelerates downward at 9.8 m/s^2. If instead you 5 points

dangina [55]

Answer:

if you need an actual number answer you can use :Vf = Vi + at. If you throw the ball it will have an initial force beside gravity accelerating the fall temporarily from greater than throw it downwards, its acceleration (in the absence of air resistance) will be greater than 9.8 m/s2 until it slows back down to a constant 9.8 m/s2 after ( t )amount of time

Explanation:

If you drop a ball, it accelerates downward at 9.8 m/s2. if instead you throw the ball straight downwards While throwing, we apply an additional force other than the gravitational force.

This gives an additional, temporary acceleration along with the gravitational acceleration.

Thus from the instant it is thrown and the instant it leaves your hand, the object is under variable acceleration, the variation of acceleration being the reason of the varying force which we do apply on the object. But once it leaves our hand it is always under constant acceleration of g which is9.8 m/s2

5 0

2 years ago

What<br> A moving object always has energy in its

elena-14-01-66 [18.8K]

The answer is a cell I think hope it helps sorry if wrong

8 0

3 years ago

A fully loaded, slow-moving freight elevator has a cab with a total mass of 1400 kg, which is required to travel upward 37 m in

kogti [31]

Answer:

789.8 W

Explanation:

mass of the cab = 1400 kg, the counter weight of the elevator = 930 kg

weight of the cab = 1400 × 9.81 where weight = mg and m is mass and g is acceleration due to gravity.

weight of the cab = 13734 N

counter weight of the elevator = 930 × 9.81 = 9123.3 N

the exerted force of the elevator = weight of the cab - counter weight of the elevator = 13734 - 9123.3 = 4610.7 N

Average power by the motor P = F × v = F × distance / time

where v is speed in m/s, and time is in seconds

P = 4610.7 × 37 / ( 3.6 × 60) = 789.80 W

where (3.6 × 60 ) is the time in seconds

6 0

3 years ago