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prisoha [69]
3 years ago
8

What are the advantages and disadvantages of DNA foresics/analysis?

Chemistry
2 answers:
Simora [160]3 years ago
7 0
Advantage: Identifications

Disadvantage: Disease Screening
ad-work [718]3 years ago
5 0
Its advantage is it helps in the transfer of hereditary materials
its disadvantage it that some time it also causes disease
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Part 1: Draw the major organic product for the proton transfer reaction between sodium hydride and ethanol; be sure to include l
valina [46]

Answer:

Major product ethoxide ion

Explanation:

  • Sodium hydride acts as a strong base towards ethanol.
  • Hydride ion abstracts one proton from -OH group in ethanol to produce sodium ethoxide and hydrogen gas.
  • It is an example of acid-base reaction where sodium hydride acts as a base and ethanol acts as an acid
  • Structure of major organic product i.e. ethoxide ion has been shown below.

4 0
3 years ago
A city in Laguna generates 0.96 kg per capita per day of Municipal Solid Waste (MSW). Makati City in Metro Manila generates 1.9
mamaluj [8]

Answer:

i) amount of MSW generated:

Laguna: 19200 Kg/day

Makati: 38000 Kg/day

ii) number of trucks to collect twice weekly:

Laguna: 3 trucks

Makati: 5 trucks

iii) volume of MSW in tons that enter landfill/week:

Laguna: 147.84 ton/week

Makati: 292 ton/week

Explanation:

i) Laguna: 0.96 Kg person / day of MSW * 20000 = 19200 Kg MSW / day

⇒ Laguna: 19200 Kg/day * ( 7day/ week ) = 134400 Kg/week

Makati: 1.9 Kg person / day of MSW * 20000 = 38000 Kg MSW / day

⇒ Makati: 38000 Kg/day * ( 7day/week ) = 266000 Kg/week

ii)  truck capacity = 4.4 ton * ( Kg / 0.0011 ton ) = 4000 Kg

⇒ quote/day = 4000 Kg * 0.75 = 3000 Kg

⇒ loads/day = 2 * 3000 kg = 6000 Kg

⇒ operate/week = 5 * 6000 Kg = 30000 Kg

∴ Laguna:  number of trucks needed/week= 134400 / 30000  = 4.48 ≅ 5 trucks

⇒ number of trucks to collect twice weekly = 5 / 2 = 2.5 ≅ 3 trucks

∴ Makati : number of trucks needed/week = 266000 / 30000 = 8.86 ≅ 9 trucks

⇒ number of trucks to collect twice weekly = 9 / 2 = 4.5 ≅ 5 trucks  

iii) enter landfill/week:

Laguna: 134400Kg MSW/week * ( 0.0011 ton/Kg ) = 147.84 ton/week

Makati: 266000Kg MSW/week * ( 0.0011 ton/Kg ) = 292 ton/week

4 0
3 years ago
Which of the following correctly describes an Arrhenius acid?
PSYCHO15rus [73]

Answer:

D.

It produces H* in solution.

4 0
3 years ago
To soften cloths in the wash it is recommended to use 2.0 g of sodium borate per liter of water. If a filled washing machine hol
Evgesh-ka [11]

% m/v of the solution = 0.2%m/v

<h3>Further explanation</h3>

\tt Percent~m/v=\dfrac{mass~solute(g)}{volume~solution(ml)}\times 100\%

or

% m/v = g solute / 100 ml solution

Concentration : 2 g sodium borate / L water

For 10 L⇒20 g Sodium borate

\tt \%m/v=\dfrac{20~g}{10,000~ml}\times 100\%\\\\\%m/v=0.2\%

4 0
3 years ago
A solution is made by dissolving 58.125 g of sample of an unknown, nonelectrolyte compound in water. The mass of the solution is
e-lub [12.9K]

Answer:

molecular weight (Mb) = 0.42 g/mol

Explanation:

mass sample (solute) (wb) = 58.125 g

mass sln = 750.0 g = mass solute + mass solvent

∴ solute (b) unknown nonelectrolyte compound

∴ solvent (a): water

⇒ mb = mol solute/Kg solvent (nb/wa)

boiling point:

  • ΔT = K*mb = 100.220°C ≅ 373.22 K

∴ K water = 1.86 K.Kg/mol

⇒ Mb = ? (molecular weight) (wb/nb)

⇒ mb = ΔT / K

⇒ mb = (373.22 K) / (1.86 K.Kg/mol)

⇒ mb = 200.656 mol/Kg

∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg

moles solute:

⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute

molecular weight:

⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol

8 0
3 years ago
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