Question

0.22 L of HNO3 is titrated to equivalence using 0.18 L of 0.2 MNaOH. What is the concentration of the HNO3?

Answer 1

Answer:

0.16 M

Explanation:

Data provided as per the question is below:-

Volume of $HNO_3$ = 0.22 L

The Volume of NaOH = 0.18 L

Morality of NaOH = 0.2

According to the given situation, the calculation of the concentration of the $HNO_3$ is shown below:-

For equivalence,

Number of the equivalent of $HNO_3$ = Number of equivalents of NaOH

$= \frac{0.18\times0.2}{0.22}$

$= \frac{0.036}{0.22}$

= 0.16363 M

or

= 0.16 M