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ryzh [129]
3 years ago
7

1. Is the sequence geometric? If so, identify the common ratio.

Physics
1 answer:
frozen [14]3 years ago
6 0
1) <span>yes;2 6*2=12 12*2=24 24*2=48
2)</span><span>Next Term (or nth term) = ar^n-1 
</span>
a = first term, i.e. 5 
<span>r = common ratio i.e. 3 (as 15/5=3 and 45/15=3 </span>
<span>n = .. </span>
<span>as you already have 1st , 2nd and 3rd terms</span>
<span>substituting now </span>
<span>T4= ar^n-1 </span>
<span>= 5*3^4-1 </span>
<span>= 5*3^3 </span>
<span>= 5*27 </span>
<span>T4 = 135 
</span>T5= ar^n-1 
<span>= 5*3^5-1 </span>
<span>= 5*3^4 </span>
<span>= 5*81 </span>
<span>T5 = 405 </span>


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V_{d} =\frac{I}{n*abs(q)*A} \\V_{d}=\frac{87.5 x10^{-2} }{5.8x^10{28} *1.6x^{-19} *5.3x^{6} }\\V_{d}=1.78 \frac{m}{s}

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