A. Getting a full set of valence electrons
Explanation:
The best description of the end result of chemical bonding for most atoms is the getting of a full set of valence electrons.
Atoms reacts with one another in order to complete valence electronic shell.
- The valence electron shell is the outermost energy level of an atom.
- It is from this energy level that electrons are lost or gained to form bonds.
- All atoms wants to be like the noble gases whose valence electronic shell is completely filled up
- This is the crux of chemical bonding
- The attraction that is produced from the interaction leads to bond formation
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<u>Explanation</u>
- The relationship between the strength of a bond (single vs double vs triple) and its wave-number on an IR spectrum as the bond strength increases the wave number increases.
STRENGTH OF BONDS TRIPLE>DOUBLE>SINGLE
WAVE NUMBER SINGLE>DOUBLE>TRIPLE
- wave number for single bond is greatest because it has greatest bond frequency among the three( more the frequency greater is the wave number).
Explanation:
If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as: v2f=2⋅m1(m2+m1)v1i+(m2−m1)(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i .
Answer:
The circular loop experiences a constant force which is always directed towards the center of the loop and tends to compress it.
Explanation:
Since the magnetic field, B points in my direction and the current, I is moving in a clockwise direction, the current is always perpendicular to the magnetic field and will thus experience a constant force, F = BILsinФ where Ф is the angle between B and L.
Since the magnetic field is in my direction, it is perpendicular to the plane of the circular loop and thus perpendicular to L where L = length of circular loop. Thus Ф = 90° and F = BILsin90° = BIL
According to Fleming's left-hand rule, the fore finger representing the magnetic field, the middle finger represent in the current and the thumb representing the direction of force on the circular loop.
At each point on the circular loop, the force is always directed towards the center of the loop and thus tends to compress it.
<u>So, the circular loop experiences a constant force which is always directed towards the center of the loop and tends to compress it.</u>
Answer:
u = - 20 cm
m =
Given:
Radius of curvature, R = 10 cm
image distance, v = 4 cm
Solution:
Focal length of the convex mirror, f:
f = 
Using Lens' maker formula:

Substitute the given values in the above formula:


u = - 20 cm
where
u = object distance
Now, magnification is the ratio of image distance to the object distance:
magnification, m =
magnification, m =
m =
m =