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Ne4ueva [31]
3 years ago
15

QUESTION 4

Physics
1 answer:
Artyom0805 [142]3 years ago
6 0

Answer:

I think the answer might be the first one

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14. What is the mass of a 250 N bag of groceries?
Veseljchak [2.6K]

Answer:

mass = 25.5kg

Explanation:

The gravitational force equivalent, or, more commonly, g-force, is a measurement of the type of force per unit mass – typically acceleration – that causes a perception of weight, with a g-force of 1 g equal to the value of gravitational acceleration on Earth, g, of about 9.8 m/s².

Mass, m = \frac{Force}{acceleration due to gravity}

mass,m=\frac{F}{g} = \frac{250}{9.8}= 25.5 kg

8 0
3 years ago
This type of bike tire is thinner, lighter, more expensive, and punctures easily.
Dmitriy789 [7]

Answer:tublar

Explanation:tublar bikes usaly cost 30-40% more

6 0
3 years ago
Read 2 more answers
A glass of water sitting in direct sunlight evaporates over time. Explain this phase change in terms of the types of heat transf
olga_2 [115]
Well over time the temperature of the water increase causeing its moleclues to move alot which causes it's state change to a gas this is who we have rain.
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3 years ago
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Discuss Joule-Thompson effect with relevant examples and formulae.
Delicious77 [7]

Answer:

\mu _j=\dfrac{1}{C_p}\left [T\left(\frac{\partial v}{\partial T}\right)_p-v\right]dp

Explanation:

Joule -Thompson effect

 Throttling phenomenon is called Joule -Thompson effect.We know that throttling is a process in which pressure energy will convert in to thermal energy.

Generally in throttling exit pressure is low as compare to inlet pressure but exit temperature maybe more or less or maybe remains constant depending upon flow or fluid flow through passes.

Now lets take Steady flow process  

Let

 P_1,T_1 Pressure and temperature at inlet and

 P_2,T_2 Pressure and temperature at exit

We know that Joule -Thompson coefficient given as

\mu _j=\left(\frac{\partial T}{\partial p}\right)_h

Now from T-ds equation

dh=Tds=vdp

So

Tds=C_pdt-\left [T\left(\frac{\partial v}{\partial T}\right)_p\right]dp

⇒dh=C_pdt-\left [T\left(\frac{\partial v}{\partial T}\right)_p-v\right]dp

So Joule -Thompson coefficient

\mu _j=\dfrac{1}{C_p}\left [T\left(\frac{\partial v}{\partial T}\right)_p-v\right]dp

This is Joule -Thompson coefficient for all gas (real or ideal gas)

We know that for Ideal gas Pv=mRT

\dfrac{\partial v}{\partial T}=\dfrac{v}{T}

So by putting the values in

\mu _j=\dfrac{1}{C_p}\left [T\left(\frac{\partial v}{\partial T}\right)_p-v\right]dp

\mu _j=0 For ideal gas.

6 0
3 years ago
Sean pushes a box with a force of 100 N. Christian pushes an identical box with a force of
kap26 [50]

Answer:

Christian

Explanation:

Given that

Force applied by Sean ,F₁=100 N

Force applied by Christian ,F₂=200 N

Lets take mass of the box =  m kg

As we know that from second law of Newton's

F= m a

F=Force,m=mass ,a=acceleration

F_1=ma_1

100=m\times a_1

a_1=\dfrac{100}{m}\ m/s^2

F_2=ma_2

200=m\times a_2

a_2=\dfrac{200}{m}\ m/s^2

From the above we can say that acceleration a₂ is greater than a₁ is for the same mass of the box.

Therefore Christian will acceleration more for the box.

5 0
3 years ago
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