I think your question should be:
An industrial laser is used to burn a hole through a piece of metal. The average intensity of the light is
What is the rms value of (a) the electric field and
(b) the magnetic field in the electromagnetic wave emitted by the laser
Answer:
a)
b)
Explanation:
To find the RMS value of the electric field, let's use the formula:
Where
;
;
Therefore
b) to find the magnetic field in the electromagnetic wave emitted by the laser we use:
;
;
I would have to say B failed because I think I read something about it being only 2law not 3
Explanation:
she ends up with a displacement of 5km north of her house and a distance of 3km
Answer:
3.6 × 10¹² nanoseconds
Explanation:
Hour is the unit of time. Seconds is the SI unit of time.
Hour and seconds are related as:
1 hour = 60 minutes
1 minute = 60 seconds
So,
1 hour = 60 ×60 seconds = 3600 seconds
Thus,
3600 seconds are in one hour
Also,
1 sec = 10⁹ nanoseconds
Thus,
3600 sec = 3600 × 10⁹ nanoseconds = 3.6 × 10¹² nanoseconds
Thus,
<u>3.6 × 10¹² nanoseconds are in one hour.</u>
Answer:2.21 x 10^-7 m
Explanation:
From the question we know that,
Phi = 9.05 x 10^-19 J
Now with Vo being the threshold frequency and h being Plancks constant, then the threshold (i.e. MINIMUM) frequency required to ionize the metal is:
Vo = 9.05 x 10^-19 / 6.626 x 10^34 J.s
= 1.36 x 10^15 s^1
The MAXIMUM wavelength this corresponds to is
Landa = C / Vo = 3 x 10^8 / 1.36 x 10^15
Wavelength = 2.21 x 10^-7m
= 2.21 x 10^-7 nm