All categories

2 years ago

What is the restoring force of a pendulum

Physics

1 answer:

salantis [7]2 years ago

3 0

Answer:

the Restoring force causes the vibrating object to go slower going further from the equilibrium position and to go faster as it approaches the equilibrium position. the restoring force is what is causing the vibration The tension force comes from the string tugging on the bob of the pendulum.

Explanation:

You might be interested in

In which part of the wave are the particles of the medium closer together?

Lesechka [4]

B.) Compressions
HOPPE IT HELPED

6 0

3 years ago

Read 2 more answers

A box is being pulled to the right. What is the direction of the gravitational force?

lapo4ka [179]

The correct answer to the question is vertically downward i.e towards the centre of earth.

EXPLANATION:

As per the question, the box is pulled to the right.

Hence, the direction of the applied force is towards right.

We are asked to determine the direction of the gravitational force that acts on the body.

Before answering this question, first we gave to understand the gravitational force of earth.

Any body present on the surface of earth is attracted with the force of gravity of earth ( gravitational force ) towards its centre. It is equivalent to the weight of the body.

The force of gravity is always directed towards the centre of earth irrespective of the nature of applied force.

Hence, the direction of the gravitational force which acts on the box is vertically downward.

7 0

3 years ago

Read 2 more answers

One cycle of the power dissipated by a resistor ( R = 800 Ω R=800 Ω) is given by P ( t ) = 60 W , 0 ≤ t < 5.0 s P(t)=60 W, 0≤

OLga [1]

Answer:

42.5W

Explanation:

To solve this problem we must go back to the calculations of a weighted average based on the time elapsed thus,

$Power_{avg} = \frac{P_1(t_1)+P_2(t_2)}{t_1+t_2}$

We need to calculate the average power dissipated by the 800\Omega resistor.

Our values are given by:

$P(t)=60 W, 0\leq t$

$P(t)=25 W, 5.0\leq t$

Aplying the values to the equation we have:

$Power_{avg} = \frac{P_1(t_1)+P_2(t_2)}{t_1+t_2}$

$Power_{avg} = \frac{60(5-0)+25(10-5)}{(5-0)+(10-5)}$

$Power_{avg} = 42.5W$

5 0

2 years ago

What is the minimum tangential velocity a space station would need to simulate earth gravity if the radius is 50 meters ?

Aneli [31]

Explanation:

angular velocity is given by

$w = \sqrt{ \frac{g}{r} }$

$w = \sqrt{ \frac{9.8}{25} }$

w = 0.626

now tangential velocity is

V = rw

= 25 x 0.626

= 15.65 m/s

5 0

2 years ago

A coin dropped in the lift it takes time 0.5 s to reach the floor when lift is staionary it takes time t when lift is moving up

BARSIC [14]

Answer:

t₁ > t₂

Explanation:

A coin is dropped in a lift. It takes time t₁ to reach the floor when lift is stationary. It takes time t₂ when lift is moving up with constant acceleration. Then t₁ > t₂, t₁ = t₂, t₁ >> t₂ , t₂ > t₁

Solution:

Newton's law of motion is given by:

s = ut + (1/2)gt²;

where s is the the distance covered, u is initial velocity, g is the acceleration due to gravity and t is the time taken.

u = 0 m/s, t₁ is the time to reach ground when the light is stationary and t₂ is the time to reach ground when the lift is moving with a constant acceleration a.

hence:

When stationary:

$s=\frac{1}{2}gt_1^2\\\\t_1^2=\frac{2s}{g} \\\\When\ moving\ with\ acceleration(a):\\\\s=\frac{1}{2}(g+a)t_2^2\\\\t_2^2=\frac{2s}{g+a}$

Hence t₂ < t₁, this means that t₁ > t₂.

4 0

2 years ago