Answer:

Explanation:
As we know that thermal expansion coefficient of aluminium is given as

now we also know that after thermal expansion the final length is given as

here we know that



now we will have


Answer:
Crystal structure
Explanation:
The repeated pattern of similar particles in a material is called crystal. Crystal structure is the largest constituent unit of a solid matter.
The fundamental identity of a crystal structure is a unit cell that is formed by the arrangement of atoms or ions in a particular manner. A crystal is defined as a regular, long-ranged repeated arrangement of unit cells.
Crystal have a sharp melting and boiling point and they give a sharp edge on being cut with a knife.
Answer:
2.2nC
Explanation:
Call the amount by which the spring’s unstretched length L,
the amount it stretches while hanging x1
and the amount it stretches while on the table x2.
Combining Hooke’s law with Newton’s second law, given that the stretched spring is not accelerating,
we have mg−kx1 =0, or k = mg /x1 , where k is the spring constant. On the other hand,
applying Coulomb’s law to the second part tells us ke q2/ (L+x2)2 − kx2 = 0 or q2 = kx2(L+x2)2/ke,
where ke is the Coulomb constant. Combining these,
we get q = √(mgx2(L+x2)²/x1ke =2.2nC
Solid metal is all different types of metals or some thing that a magnet can pick up that's a full hard solid
but a non metal is everything not metal that's a solid like plastic a hot glue gun can burn throught plastic and not metal
so in conclusion metal is stronger and thicker than non modal things
Explanation:
It s given that,
Mass of a planet, 
Radius of a planet, 
(1) We need to find the acceleration due to gravity for a person on the surface of the planet. Its formula is given by :



(2) The escape velocity is given by :


v = 7324.61 m/s
Hence, this is the required solution.