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Verizon [17]
3 years ago
15

Change the speed 0.200 cm/s to units kilometers per year

Physics
1 answer:
klasskru [66]3 years ago
5 0
The Speed In Kilometers per year is 63.072.
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A particle with a charge of 2e moves between two points which have a potential difference of 75V. What is the change in potentia
Sonbull [250]
Electric potential energy is defined as Ep=Q*V where Q is the magnitude of the charge and V is the potential difference. So when a charge moves between the points that have a potential difference, it's energy changes. 

In our case: 

Q=2e=2*(-1.6*10^-19) C
V=75 V

Ep=(-3.2*10^-19)*75

Ep=-2.4*10^-17 J

The change in potential energy of the charge is -2.4*10^-17 J 
5 0
3 years ago
How much work does it take to lift 345 boxes to a height of 6.00 m of each box has a mass of 7.89 kg
Art [367]

Given the value of the mass of each boxes, the work done in lifting the boxes to the given height is 1.6 × 10⁵J.

<h3>Work done</h3>

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = F × d

Where F is force applied or Weight and d is distance

Also Force = Weight = mass × acceleration due to gravity.

Since gravity is acting on the boxes as it been lift

W = Weight × height from ground level

W = mg × d

Where m is mass of the boxes, g is accelration due to gravity( g = 9.8m/s² ) and d is distance from ground level.

Given the data in the question;

  • Since each box has a mass of 7.89 kg
  • Mass of the 345 boxes = 345 × 7.89 kg = 2722.05kg
  • Distance or height d = 6.0m
  • Work done W = ?

To determine the work done, we substitute our values into the expression above.

W = mg × d

W = 2722.05kg × 9.8m/s² × 6.0m

W = 160056.5kgm²/s²

W = 160056.5J

W = 1.6 × 10⁵J

Therefore,  Given the value of the mass of each boxes, the work done in lifting the boxes to the given height is 1.6 × 10⁵J.

Learn more about work done here: brainly.com/question/26115962

3 0
3 years ago
A 3.9 kg ball traveling towards a soccer player at a velocity of -3.5 m/s rebounds off the soccer player's foot at a velocity of
Tresset [83]

Answer: 2.92 s

Explanation:

Given

Mass of ball is m=3.9\ kg

The initial velocity of the ball is u=-3.5\ m/s

Velocity after the rebound is v=15.9\ m/s

Force during the contact is F=25.9\ N

We know, change in momentum is Impulse

\Rightarrow F\cdot \Delta t=m(\Delta v)

\Rightarrow 25.9\cdot \Delta t=3.9(15.9-(-3.5))\\\\\Rightarrow \Delta t=\dfrac{3.9\times 19.4}{25.9}=2.92\ s

Thus, the force is applied for 2.92 s

4 0
3 years ago
The sound from a bolt of lightning travelled 4.08 km in 12.0 s. What was the speed
LenaWriter [7]

Answer:

83.67 m/s

Explanation:

Set up a calculation to convert units of measure to what you need.

You have km/s and you need m/s.

4.08km     1000 m         83.67m

-----------  X ----------  =  ---------------   the km will cancel out and you are left

 12.0 s          1 km              s              with m/s

6 0
3 years ago
Describe a situation when you might travel at a high velocity bit with low acceleration
iren [92.7K]

I am sitting in my seat.
I am listening to my mp3 and reading my book.
My eyes are getting heavy.  They start to close.
I try to stay awake, but it's no use.
I am so warm and comfortable and sleepy,
and I have just finished my dinner.
Finally I can't help it.  Resistance is futile.
I give up, and fall deep asleep.
My head rests back against my soft, comfy seat.

My seat is in row 26 on the airplane I'm flying in
to visit my grandmother on the coast.
We are cruising at 560 miles an hour, bearing 280°,
at flight level 320 .
The temperature outside my window is  -60°F .

5 0
3 years ago
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