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Ahat [919]
3 years ago
12

Assuming that the density of vinegar is 1.005 g/mL, calculate the molarity of acetic acid in vinegar from your average value for

the mass percentage of acetic acid in vinegar. Density of vinegar= 1.005 g/mL Average mass % acetic acid= 5.2%,
Chemistry
1 answer:
Lapatulllka [165]3 years ago
4 0
We can divide this problem into 4 steps:
Step 1: Calculate mass of one liter solution from the density
Mass of solution = 1000 ml soln x \frac{1.005g soln}{1 mL} =1005 g soln
Step 2: Calculate the mass of acetic acid
Mass of CH₃COOH = 1005 g soln x (5.2 g / 100 g soln) = 52.26 g acetic acid
Step 3: Calculate the moles of acetic acid:
52.26 g acetic x (1 mole acetic / 60 g acetic) = 0.871 mol
step 4: Calculate the molarity of acetic acid:
molarity = moles of acetic / liters of soln = 0.871 / 1 L = 0.871 mole / L 

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Answer:

CH2FCOOH > CH2ClCOOH > CH2BrCOOH > CH3COOH

Explanation:

CH2FCOOH > CH2ClCOOH > CH2BrCOOH > CH3COOH

More electronegative atom of halogen is , stronger acid will be.

6 0
3 years ago
A student found that the titration had taken 10.00 ml of 0.1002 m naoh to titration 0.132 g of aspirin, a monoprotic acid. calcu
Harman [31]
The balanced equation for the reaction between NaOH and aspirin is as follows;
NaOH + C₉H₈O₄ --> C₉H₇O₄Na + H₂O
stoichiometry of NaOH to C₉H₈O₄ is 1:1
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4 0
3 years ago
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How does advertising affect the sales of orbit white
MAXImum [283]
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3 0
3 years ago
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d. Hydrophobic molecules are attracted to each other.

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4 0
3 years ago
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