A 360-N child is in a swing that is attached to a pair of ropes 1.90 m long. Find the gravitational potential energy of the chil
1 answer:
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Let's choose east as positive x-direction and south as positive y-direction. We can resolve the two displacement along these two axes:
- Displacement 1 (3.5 km, south of west
- Displacement 2 (2.7 km, east of south
So, the total components on the two directions are
And the magnitude of the hiker's resultant displacement is
Answer:
The acceleration required by the rocket in order to have a zero speed on touchdown is 19.96m/s²
The rocket's motion for analysis sake is divided into two phases.
Phase 1: the free fall motion of the rocket from the height 2.59*102m to a height 86.9m
Phase 2: the motion of the rocket due to the acceleration of the rocket also from the height 86.9m to the point of touchdown y = 0m.
Explanation:
The initial velocity of the rocket is 0m/s when it started falling from rest under free fall. g = 9.8m/s² t1 is the time taken for phase 1 and t2 is the time taken for phase2.
The final velocity under free fall becomes the initial velocity for the accelerated motion of the rocket in phase 2 and the final velocity or speed in phase 2 is equal to zero.
The detailed step by step solution to the problems can be found in the attachment below.
Thank you and I hope this solution is helpful to you. Good luck.
