What’s the answer please?

Astronaut rachel leaves earth in a spaceship at a speed of 0.960c relative to an observer on earth. rachel's destination is a st

insens350 [35]

Utilizing Lorentz factor;

Lorentz factor = Sqrt (1-u^2/c^2), where u = initial velocity, c = speed of light

But, u/c = 0.960

Therefore,
Lorentz factor = Sqrt (1-0.960^2) = 0.28

For an observer,
t = (Distance to the star*Lorentz factor)/ (u/c) = (14.4*0.28)/0.96 = 4.2 years

4 0

4 years ago

I need help with this

Tanzania [10]

While ice melts, it remains at 0 °C, and the liquid water that is formed with the latent heat of fusion is also at 0 °C. The heat of fusion for water at 0 °C is approximately 334 joules per gram, and the heat of vaporization at 100 °C is about 2,230 joules per gram. So it will be C

7 0

4 years ago

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The magnetic field 40.0 cm away from a long, straight wire carrying current 2.00 A is 1.00μT. (a) At what distance is it 0.100μ

maw [93]

The distance should be 4m from the wire in order to get the magnetic field of 0.100μ .

The magnitude and direction of the magnetic field due to a straight wire carrying current can be calculated using the previously mentioned Biot-Savart law. Let "I" be the current flowing in a straight line and "r" be the distance. Then the magnetic field produced by the wire at that particular point is given by $B=\frac{u_0I}{2\pi r}$ ...(1)
Since the wire is assumed to be very long, the magnitude of the magnetic field depends on the distance of the point from the wire rather than the position along the wire.

It is given that magnetic field 40.0 cm away from a straight wire is 1.00μT having current 2.00 A .

From equation (1) magnetic field 40.0 cm = 0.4m away from a straight wire is 1.00μT which is given by $1.00=\frac{u_0I}{2\pi \times0.4}$ .....(2)

From equation (1) magnetic field 'r' m away from a straight wire is 0.100μT which is given by $0.100=\frac{u_0I}{2\pi \times r}$ ...(3)

On dividing equation (2) by (3) , we get

$\frac{1}{0.1} =\frac{r}{0.4} \\\\r=4m$

Learn more about magnetic field here :

brainly.com/question/27939568

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4 0

2 years ago

The standard unit for measuring volume is the _____. milliliter liter deciliter cubic centimeter

Natali [406]

Cubic centimeter is the answer

8 0

4 years ago

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A 0.500-kg mass suspended from a spring oscillates with a period of 1.18 s. How much mass must be added to the object to change

olga55 [171]

Answer:

The add mass = 5.465 kg

Explanation:

Note: Since the spring is the same, the length and Tension are constant.

f ∝ √(1/m)........................ Equation 1 (length and Tension are constant.)

Where f = frequency, m = mass of the spring.

But f = 1/T ..................... Equation 2

Substituting Equation 2 into equation 1.

1/T ∝ √(1/m)

Therefore,

T ∝ √(m)

Therefore,

T₁/√m₁ = k

where k = Constant of proportionality.

T₁/√m₁ = T₂/√m₂ ........................ Equation 3

making m₂ the subject of the equation

m₂ = T₂²(m₁)/T₁²........................... Equation 4

Where T₁ = initial, m₁ = initial mass, T₂ = final period, m₂ = final mass.

Given: T₁ = 1.18 s m₁ = 0.50 kg, T₂ = 2.07 s.

Substituting into equation 4

m₂ = (2.07)²(0.5)/(1.18)²

m₂ = 4.285(1.392)

m₂ = 5.965 kg.

Added mass = m₂ - m₁

Added mass = 5.965 - 0.5

Added mass = 5.465 kg.

Thus the add mass = 5.465 kg

7 0

3 years ago