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Anni [7]
2 years ago
15

1) Why are the antimony and beryllium ions so small? Differentiate between the causes.

Chemistry
2 answers:
SSSSS [86.1K]2 years ago
5 0
<h2>Antimony and Berllium</h2>

The antimony and beryllium ions are so small because atomic number of antimony and beryllium is 51 and 4. Beryllium tends to lose 2 electrons to form beryllium ions (Be2+) so it forms 4 coordinated complex ions, it does not form simple ions. Antimony gains 3 electrons to become stable or form an ion (Sb+3) so these ions are small.

Both ions and atoms tend to grow larger as we go down the periodic table because protons are added and atomic number increases. So new shells are also added. The new energy shells provide shielding effect so atomic size increases going down the group in the periodic table.


Viefleur [7K]2 years ago
4 0
1. For this question, the adjective small must be percepted in a relative sense. This is because it is not the smallest ion (that would be hydrogen). It could be that the antimony and beryllium ions are smaller compared to their neutral forms. This is because they donate electrons when ionized. As a result, the electrons are reduced, so does the electron cloud which makes the radius much smaller.

2. The periodic table is arranged in terms of increasing atomic number. For neutral atoms, the number of protons (atomic number) is equal to the number of electrons. So, the farther we go down the table, the higher the atomic number. The higher the atomic number, the bigger the electron cloud which makes the atomic radius bigger. Because by definition, atomic radius is the length from the nucleus to the farthest electron from the nucleus.
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When 61.6 g of alanine (C3H7NO2) are dissolved in 1150. g of a certain mystery liquid X, the freezing point of the solution is 2
MrRissso [65]

Answer:

Explanation:

From the given information:

TO start with the molarity of the solution:

= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ C_3H_7 NO_3}{89.1 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}

= 0.601 mol/kg

= 0.601 m

At the freezing point, the depression of the solution is \Delta \ T_f = T_{solvent}- T_{solution}

\Delta \ T_f = 2.9 ^0 \ C

Using the depression in freezing point, the molar depression constant of the solvent K_f = \dfrac{\Delta T_f}{m}

K_f = \dfrac{2.9 ^0 \ C}{0.601 \ m}

K_f = 4.82 ^0 C / m}

The freezing point of the solution \Delta T_f = T_{solvent} - T_{solution}

\Delta T_f = 7.3^ 0 \ C

The molality of the solution is:

= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ NH_4Cl}{53.5 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}

Molar depression constant of solvent X, K_f = 4.82 ^0 \ C/m

Hence, using the elevation in boiling point;

the Vant'Hoff factor i = \dfrac{\Delta T_f}{k_f \times m}

i = \dfrac{7.3 \ ^0 \ C}{4.82 ^0 \ C/m \times 1.00 \ m}

\mathbf {i = 1.51 }

3 0
2 years ago
In the reaction below how would adding more of product C affect the equilibrium of the system? A+B arrows both ways C+D
Shalnov [3]

Answer:

1. The reaction will proceed backward, shifting the equilibrium position to the left.

2. The reaction will proceed forward, shifting the equilibrium position to the right.

3. Either add more of the products ( H2O or Cl2) or remove the reactant (HCl or O2)

Explanation:

3 0
3 years ago
Sulfuric acid dissolves aluminum metal according to the following reaction:
Fiesta28 [93]

Answer:

m_{H_2SO_4}=81.7gH_2SO_4

m_{H_2}=1.67gH_2

Explanation:

Hello,

Based on the given undergoing chemical reaction is is rewritten below:

2Al (s) + 3H_2SO_4 (aq)\rightarrow  Al _2(SO4)_3 (aq) + 3H_2 (g)

By stoichiometry we find the minimum mass of H2SO4 (in g) as shown below:

m_{H_2SO_4}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2SO_4}{2molAl}*\frac{98gH_2SO_4}{1molH_2SO_4} \\m_{H_2SO_4}=81.7gH_2SO_4

Moreover, mass of H2 gas (in g) would be produced by the complete reaction of the aluminum block turns out:

m_{H_2}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2}{2molAl}*\frac{2gH_2}{1molH_2} \\m_{H_2}=1.67gH_2

Best regards.

3 0
3 years ago
How does the number of valence electrons for elements change across a period?
NeTakaya
D. The number increases and then decreases for noble gases
4 0
3 years ago
Read 2 more answers
How can you use a heating curve to find the melting and boiling point
lana66690 [7]

Answer:

Explanation:

A heating curve graphically represents the phase transitions that a substance undergoes as heat is added to it. ... The first change of phase is melting, during which the temperature stays the same while water melts. The second change of phase is boiling, as the temperature stays the same during the transition to gas.

3 0
3 years ago
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