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Anni [7]
2 years ago
15

1) Why are the antimony and beryllium ions so small? Differentiate between the causes.

Chemistry
2 answers:
SSSSS [86.1K]2 years ago
5 0
<h2>Antimony and Berllium</h2>

The antimony and beryllium ions are so small because atomic number of antimony and beryllium is 51 and 4. Beryllium tends to lose 2 electrons to form beryllium ions (Be2+) so it forms 4 coordinated complex ions, it does not form simple ions. Antimony gains 3 electrons to become stable or form an ion (Sb+3) so these ions are small.

Both ions and atoms tend to grow larger as we go down the periodic table because protons are added and atomic number increases. So new shells are also added. The new energy shells provide shielding effect so atomic size increases going down the group in the periodic table.


Viefleur [7K]2 years ago
4 0
1. For this question, the adjective small must be percepted in a relative sense. This is because it is not the smallest ion (that would be hydrogen). It could be that the antimony and beryllium ions are smaller compared to their neutral forms. This is because they donate electrons when ionized. As a result, the electrons are reduced, so does the electron cloud which makes the radius much smaller.

2. The periodic table is arranged in terms of increasing atomic number. For neutral atoms, the number of protons (atomic number) is equal to the number of electrons. So, the farther we go down the table, the higher the atomic number. The higher the atomic number, the bigger the electron cloud which makes the atomic radius bigger. Because by definition, atomic radius is the length from the nucleus to the farthest electron from the nucleus.
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Considering the temperature vs. time graph below, how does the temperature at the beginning of a change of state
Cloud [144]

Answer:

The temperature is always lower.

Explanation:

The temperature is always lower at the end of the state as compared to beginning of the state. We can see in the given data, the temperature is higher at the beginning i. e. 140 degree Celsius but with the passage of time, the temperature of a state decreases constantly  and the temperature at the end is lower i. e. 20 degree Celsius. So we can conclude that the temperature is always lower.

6 0
3 years ago
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6 0
3 years ago
A gas expands from a volume of 2.00L at 36.0oC to a volume of 2.50 L, what is the final temperature, if the pressure is constant
lakkis [162]
We shall consider V, the volume and T, the temperature.
According to Boyle's Laws:
\frac{V1}{T1} = \frac{V2}{T2}
In our case:
\frac{2.00}{36.0} = \frac{2.50}{T2} =\ \textgreater \  T2= \frac{2.50*36.00}{2.00} = 45
6 0
3 years ago
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The specific heat capacity of an unknown metal is 0.343 J/(g•°C). Calculate the energy required to raise the temperature of 224
Margarita [4]

Explanation:

the answer and explanation is in the picture

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8 0
3 years ago
Calculate the work, w, gained or lost by the system when a gas expands from 15 L to 45 L against a constant external pressure of
marta [7]

Answer:

Work done by the system = 4545 J

Explanation:

The expression for the calculation of work done is shown below as:

w=-P\times \Delta V

Where, P is the pressure

\Delta V is the change in volume

From the question,  

\Delta V = 45 - 15 L = 30 L

P = 1.5 atm

w=-1.5\times 30\ atmL

Also, 1 atmL = 101 J

So,  

w=-1.0\times0.75\times 101\ J=-4545\ J (negative sign implies work is done by the system)

<u>Work done by the system = 4545 J</u>

6 0
3 years ago
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