According to the balanced equation of this reaction:
N2(g) + 3H2(g) ↔ 2NH3(g)
and when we have Kp = 4.51 x 10^-5 so, in the Kp equation we will substitute by the value of the P for each gas to compare the value with Kp = 4.51x10^-5
a) when we have 98 atm NH3, 45 atm N2, 55 atm H2 by substitution in Kp equation:
Kp= [p(NH3)]^2 / [p(N2)]*[p(H2)]^3 = [98]^2 / [45]*[55]^3
= 1.28x10^-3
So here the value is higher than the value of the given Kp.
so the reaction will go leftwards toward the reactants ( to reduce the value of Kp) to reach the equilibrium.
b) When 57 atm NH3, 143 atm N2, No H2 so like a) by substitution:
Kp = [57]^2 / [143] = 22.7
So the reaction will go leftwards toward the reactants to reduce the value of Kp to reach equilibrium.
c) when 13 atm NH3, 27 atm N2, 82 H2
Kp = [13]^2 / [27]*[82]^3 = 1.135 x 10^-5 So this value is lower than the Kp which is given.
so, the reaction will go towards the right toward the products to increase the value of Kp to reach the equilibrium.
Answer:
Three! 3
Explanation:
O2 means that there are two oxygen and I is just one
Answer:
0.027 mole of NaOH.
Explanation:
We'll begin by obtaining the number of mole H2SeO4 in 45mL of 0.30M H2SeO4
This is illustrated below:
Molarity of H2SeO4 = 0.3M
Volume of solution = 45mL = 45/1000 = 0.045L
Mole of H2SeO4 =...?
Mole = Molarity x Volume
Mole of H2SeO4 = 0.3 x 0.045
Mole of H2SeO4 = 0.0135 mole
Next, the balanced equation for the reaction. This is given below:
H2SeO4 + 2NaOH –> Na2SeO4 + 2H2O
From the balanced equation above,
1 mole of H2SeO4 required 2 moles of NaOH.
Therefore, 0.0135 mole of H2SeO4 will require = 0.0135 x 2 = 0.027 mole of NaOH.
Therefore, 0.027 mole of NaOH is needed for the reaction.
The name of the ion is Copper.
<u>Explanation</u>:
- Copper is a chemical element symbolized as Cu. It has different ions, one of which is Cu(2+) and Cu(1+).
- Copper on losing 2 electrons forms the ion Cu(2+)
- Copper(2+) is an ion that carries double positive charge.
- It plays the role of a cofactor.
- It is also more stable than the single positive ion Cu(1+)
Answer:
option D = N₂ + 3H₂ → 2NH₃
Explanation:
The reaction in which the nitrogen and hydrogen are reacted to form the ammonia is true.
N₂ + 3H₂ → 2NH₃
In this reaction we can see that one molecules of nitrogen react with three molecules of hydrogen and form two molecules of ammonia.
while the other options are in correct because,
2SO₂ + O₂ → 2SO₃
In this reaction two molecules of SO₂ react with one molecule of oxygen and form two molecules of SO₃.
2H₂S + 3O₂ → 2SO₂ + 2H₂O
In this reaction two molecules of H₂S react with three molecules of oxygen and produced four molecules of product.
SnO₂ + 2H₂ → Sn + 2H₂O
This is also incorrect because three molecules of reactant form three molecules of product.
