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timofeeve [1]
3 years ago
7

In which reaction do four total molecules of reactants produce two total molecules of products?

Chemistry
1 answer:
Pachacha [2.7K]3 years ago
5 0

Answer:

option D = N₂ + 3H₂   →   2NH₃

Explanation:

The reaction in which the nitrogen and hydrogen are reacted to form the ammonia is true.

  N₂ + 3H₂   →   2NH₃

In this reaction we can see that one molecules of nitrogen react with three molecules of hydrogen and form two molecules of ammonia.

while the other options are in correct because,

2SO₂  +  O₂    →   2SO₃

In this reaction two molecules of SO₂ react with one molecule of oxygen and form two molecules of SO₃.

2H₂S  +  3O₂   →     2SO₂ + 2H₂O

In this reaction two molecules of H₂S react with three molecules of oxygen and produced four molecules of product.

SnO₂ +  2H₂   →  Sn + 2H₂O

This is also incorrect because three molecules of reactant form three molecules of product.

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(a) rate = -(1/3) Δ[O₂]/Δt = +(1/2) Δ[O₃]/Δt  

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<em>where, a and b are the coefficients of de reactant X and product Y, respectively.        </em>

(a) Based on the definition above, we can express the rate of reaction (2) as follows:      

3O₂(g) → 2O₃(g) (2)    

rate = -\frac{1}{3} \frac{\Delta[O_{2}]}{\Delta t} = +\frac{1}{2} \frac{ \Delta[O_{3}]}{ \Delta t} (3)

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+\frac{\Delta[O_{3}]}{ \Delta t} = -\frac{2}{3} \frac{\Delta[-1.61 \cdot 10^{-5}]}{ \Delta t}          

\frac{\Delta[O_{3}]}{ \Delta t} = 1.07 \cdot 10^{-5} \frac{mol}{Ls}

So the rate of appearance of O₃ is 1.07x10⁻⁵ mol/Ls.

           

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