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timofeeve [1]
3 years ago
7

In which reaction do four total molecules of reactants produce two total molecules of products?

Chemistry
1 answer:
Pachacha [2.7K]3 years ago
5 0

Answer:

option D = N₂ + 3H₂   →   2NH₃

Explanation:

The reaction in which the nitrogen and hydrogen are reacted to form the ammonia is true.

  N₂ + 3H₂   →   2NH₃

In this reaction we can see that one molecules of nitrogen react with three molecules of hydrogen and form two molecules of ammonia.

while the other options are in correct because,

2SO₂  +  O₂    →   2SO₃

In this reaction two molecules of SO₂ react with one molecule of oxygen and form two molecules of SO₃.

2H₂S  +  3O₂   →     2SO₂ + 2H₂O

In this reaction two molecules of H₂S react with three molecules of oxygen and produced four molecules of product.

SnO₂ +  2H₂   →  Sn + 2H₂O

This is also incorrect because three molecules of reactant form three molecules of product.

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Purest form of carbon is
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Obtención. El carbono se encuentra - frecuentemente muy puro - en la naturaleza, en estado elemental, en las formas alotrópicas diamante y grafito. El material natural más rico en carbono es el carbón (del cual existen algunas variedades). Grafito: Se encuentra en algunos yacimientos naturales muy puro.

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What is the salt formers group number is?
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The halogens are five non-metallic elements found in group 17 of the periodic table. The term "halogen" means "salt-former" and compounds containing halogens are called "salts". All halogens have 7 electrons in their outer shells, giving them an oxidation number of -1.

3 0
3 years ago
25. 00 ml of a buffer solution contains 0. 500 m hclo and 0. 380 m naclo. if 50. 00 ml of water is added to the buffer, what are
geniusboy [140]

The new concentrations of HClO and NaClO are  0.25M and 19M

Calculation of number of moles of each component,

Molarity of HClO = number of moles/volume in lit =  0. 500 M

Number of moles = molarity  of HClO× volume in lit = 0. 500 M× 0.025 L

Number of moles of HClO = 0.0125 mole

Molarity of NaClO  = number of moles/volume in lit =  0. 38 M

Number of moles = molarity of NaClO × volume in lit = 0. 38 M× 0.025 L

Number of moles of  NaClO  = 0.95 mole

Calculation of new concentration at volume 50 ml ( 0.05L)

Molarity of HClO = number of moles/volume in lit = 0.0125 mole/0.05L

Molarity of HClO = 0.25M

Molarity of NaClO  = number of moles/volume in lit = 0.95mole/0.05L

Molarity of NaClO  = 19 M

learn about  Molarity

brainly.com/question/8732513

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5 0
2 years ago
In an isothermal gas chromatography experiment using an ECD detector, 1.69 nmols of nchlorohexane, C6H13Cl, was added as an inte
prohojiy [21]

Answer:

The amount of Chlorodecane in the unknown is 0.105nmols

Explanation:

a) Since the GC is in an isothermal state, Chlorohexane C6H13Cl (1.69 nmols) because of its lower boiling point will elute first and Chlorodecane C12H21Cl will elute second.

The area of the first peak corresponding to Chlorohexane is 32434 units.

The area of the second peak corresponding to chlorodecane is 2022 units.

Since the response factor of the compound is not given in question and considering the response factor is same for both the compounds, the answer will be as follow:

1.69 nmols of Chlorohexane gives 32434 units

How much of chlorodecane gives 2022 units

By cross multiplication;

Moles of Chlorodecane = 2022*1.69/32434

                                         =0.105nmols

4 0
3 years ago
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