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s2008m [1.1K]
3 years ago
7

Different satellites orbit the earth with a vast range of altitudes, from just a couple hundred km, all the way to tens of thous

ands of km above the surface. The international space station (ISS) is in a low earth orbit, just 400km above the surface (you can see it with the naked eye at sunset and sunrise as a bright, moving dot). At this altitude, the acceleration due to gravity has a value of 8.69m/s Assuming that the radius of the earth is 6400km).
1. What is the speed of the ISS? Express your answer to three significant figures and include the appropriate units.
2. What is the orbital period (T) of the ISS in minutes?
Physics
1 answer:
fenix001 [56]3 years ago
3 0

Answer:

a)  v = 7.69 10³ m / s,  b)    T = 92.6 min

Explanation:

a) For this exercise we use the centripetal acceleration ratio, which in itself assumes a circular orbit, is equal to the acceleration of gravity

          a = v² / r

          v = \sqrt{a r}

the distance to the ISS is

           r = R_earth + d

           r = 6400 10³ + 400 10³

           r = 6800 10³ m

we calculate

           v = \sqrt{8.69  \ 6800 \ 10^3}Ra (8.69 6800 103)

           v = \sqrt{59.09 \ 10^6}

           v = 7.687 10³ m / s

           

the result with the correct significant figures

            v = 7.69 10³ m / s

b) The speed of the ISS is constant, so we can use the uniform motion relationships

            v = d / t

if distance is the orbit distance

            d = 2π r

time is called period

            v = 2π r / T

            T = 2π r / v

let's calculate

            T = 2π 6800 10³ /7,687 10³

            T = 5.558 10³ s

let's reduce the period to minutes

            T = 5.558 10³ s (1 min / 60s)

            T = 9.26 10¹ min

            T = 92.6 min

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Answer:

v = 2.94 m/s

Explanation:

When the spring is compressed, its potential energy is equal to (1/2)kx^2, where k is the spring constant and x is the distance compressed. At this point there is no kinetic energy due to there being no movement, meaning the net energy in the system is (1/2)kx^2.

Once the spring leaves the system, it will be moving at a constant velocity v, if friction is ignored. At this time, its kinetic energy will be (1/2)mv^2. It won't have any spring potential energy, making the net energy (1/2)mv^2.

Because of the conservation of energy, these two values can be set equal to each other, since energy will not be gained or lost while the spring is decompressing. That means

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3 0
2 years ago
In the middle of a thunderstorm, a lightning bolt flashes. It takes Roberto 5 seconds to
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Answer:

 v = 344.1 m / s    

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Explanation:

For this problem we must calculate the speed of sound in air at 22ºC

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we calculate

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5 0
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Which describes the process of conduction?
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I think the correct answer from the choices listed above is option A. The process of conduction is described by the heat energy is transferred from the land to the air by direct contact. Conduction is the process of heat transfer that happens through the collisions between molecules.
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In Millikan’s experiment, the oil droplets acquire one or more negative charges by combining with the negative charges that are
alina1380 [7]

Answer:

-9.6\cdot 10^{-19} C

Explanation:

The charge of a single electron is:

q=-1.60\cdot 10^{-19} C

If a droplet contains N electrons, then its charge would be:

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In this case, the droplet has

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tatiyna

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<h3>What is a pendulum?</h3>

A pendulum swings back and forth and can be used to show the change of potential energy to kinetic energy and vice versa.

Given that the kinetic energy is converted to the potential energy; the potential energy at 0.5 m is 3 * 9.8 * 0.5 = 14.7 J.

Following the principle of energy conservation, the kinetic energy of the pendulum at 0.5 m is 14.7 J.

Learn more about pendulum:brainly.com/question/14759840

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