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Citrus2011 [14]
2 years ago
10

When nonpolar solutes are placed in water, the hydrogen bonding network of water is disrupted, and there are fewer ways for wate

r to hydrogen-bond with itself. Is this an increase or decrease in entropy?
Chemistry
1 answer:
satela [25.4K]2 years ago
5 0

Answer:  increase in entropy

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from  an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

\Delta S is positive when randomness increases and \Delta S is negative when randomness decreases.

When the non polar solutes are placed in water, the hydrogen bonding network of water is disrupted, and there are fewer ways for water to hydrogen-bond with itself. That means the water molecules are more randomly arranged and thus have more entropy and thus \Delta S is positive.                

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Explanation:

The given data for case (1) is as follows.

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Assuming that a rectangular slab is placed above the pipe and we will calculate the heat transfer as follows.

              Q = kA \frac{\Delta T}{L}

  where,    A = area

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Therefore, putting the given values into the above formula as follows.

            Q = kA \frac{\Delta T}{L}

                = 0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{0.2}

                = 168 W

For case (2), h = 180 cm = 1.8 m

Therefore, heat lost will be calculated as follows.

                       Q = kA \frac{\Delta T}{L}

                           = 0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{1.8}

                           = 18.67 W

Thus, we can conclude that 18.67 W heat lost if the pipe was buried at a depth of 180 cm.

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More information so I can answer please.

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