Answer:
(a) = 0 N
(b) = 2.4 N
Explanation:
given
box of banana weight = 40.0 N
coefficient of static friction μ = 0.40
coefficient of kinetic friction = 0.20
a). when no horizontal force is applied .
according to Newton 's third law of motion If there is no force applied to the box,so the frictional force exerted is 0 N
b) magnitude of friction force
box and the box is initially at rest
friction force =.Static friction coefficient × weight of the box
friction force = 0.40 × 6
friction force = 2.4 N
Answer:
ω = 0.571 rad/s
Explanation:
given data
radius = 30 m
solution
we take here g = 9.8 m/s²
and g is express as
g = r × ω² ....................1
put here value and we get
9.8 = 30 × ω²
solve it we get
ω = 0.571 rad/s
Answer:
0.5 kg
Explanation:
The momentum of an object is defined as
p = mv
where
m is the mass
v is the velocity
In this problem we have,
v = 15 m/s is the velocity of the stone
p = 7.5 kg m/s is the momentum
Solving for m, we can find the mass of the stone:
The displacement of the bird is 1.8 km...because displacement is the distanse of the object from mean position to the travelled position.....hope it helps
