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2 years ago

How much net force is required to accelerate a 2000 kg car at 3.00 m/s^2

Physics

1 answer:

andrezito [222]2 years ago

6 0

The net force required to accelerate a car is 6000 N.

Force is defined as the product of the mass and acceleration of the body. Force is used to changing the velocity that is to accelerate an object or a body of a particular mass. The unit of Force is Newton or kg m/s^2.

The formula used to calculate the net force is :

F = ma

where, F = Force

m = mass = 2000 kg

a = acceleration = 3.00 m/s^2

∴ F = 2000*3

F = 6000 N

Thus, to accelerate the car at 3.00 m/s^2 of mass 2000 kg net force required is 6000 N.

To learn more about force,

brainly.com/question/1046166

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Einhorn and Finkle are in a convenience store together. For a while they talk about stealing hot dogs and deodorant, for they ar

dangina [55]

We can conclude that Einhorn decides not to steal according to the pre-conventional level where as Finkle decides per the conventional level according to Kohlberg's theory.

Explanation:

Kohlberg's theory is explained in three stages:

The pre-conventional stage where sense of moral is controlled externally by rules of authority figures such as parents and teachers.An action is viewed according to the results obtained after the act.
Conventional stage is when a person's morals are controlled by authority figures and their positive relation to the society norms.
Post-conventional level relies on a person's principles and values where some laws are seen as unjust.

In this case, Einhorn recognizes that if you steal, you might end up being caught and punished because it is not accepted by authority figures and could led to punishment. This is stage one. Finkle recognizes that stealing is unaccepted by the law and people in a society should avoid it.This is stage two.

We can conclude that Einhorn's decision not to steal is influenced by the pre-conventional level where as Finkle's by the conventional level according to Kohlberg's theory of moral development.

Learn More

Kohlberg's theory of moral development : brainly.com/question/8885213

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4 years ago

A moving object has a kinetic energy of 150J and a momentum of 20.3kgxm/s find the speed of the object in m/s

Irina-Kira [14]

Answer:

$v = 14.78m/s$

Explanation:

Given

$KE = 150J$

$p = 20.3kgm/s$

Required

Determine the object's speed

Kinetic Energy is calculated as:

$KE = \frac{1}{2}mv^2$

Make m the subject

$m = \frac{2KE}{v^2}$

Momentum is calculated as:

$p = mv$

Make m the subject

$m = \frac{p}{v}$

So, we have:

$m = \frac{p}{v}$ and $m = \frac{2KE}{v^2}$

Equate both expressions: $m = m$

$\frac{2KE}{v^2} = \frac{p}{v}$

Multiply both sides by v

$v * \frac{2KE}{v^2} = \frac{p}{v}*v$

$\frac{2KE}{v} = p$

Make v the subject

$v = \frac{2KE}{p}$

Substitute $KE = 150J$ and $p = 20.3kgm/s$

$v = \frac{2 * 150}{20.3}$

$v = \frac{300}{20.3}$

$v = 14.78m/s$

5 0

3 years ago

At 1:00 a.m., someone breaks a window in the back of a store and robs the safe. On the way out, the thief is cut on a piece of b

Karolina [17]

Answer:dd

Explanation:

5 0

3 years ago

Andy pushes a box to the right with 5 N of force. Kristen pushes the box to the left with 3 N of force. What will be the resulti

REY [17]

The forces are applied in opposite direction.
So the net force will be the difference of both forces.
net force =5-3=2N

This force will be in direction of 5N(bigger force) means in direction which Andy is pushing.

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3 years ago

A 50 kg bumper car with a 40 kg child and it is at rest when a 60 kg child in her own bumper car slams into it the collision las

IrinaK [193]

Answer:

F = 99 v₂₀

v₂₀ = 1 m / s, F = 99 N

Explanation:

In this exercise it is asked to find the force during the collision, for this we use the relationship between the momentum and the momentum of car 1

I = Δp

F t = p_f- p₀

F t = m (v_f -v₀) (1)

We must find the final speed of car 1, for this we define a system formed by the two cars, in this case the forces during the collision are internal and the moment is conserved

initial instant. Before the crash

p₀ = 0 + m₂ v₂₀

final instant. After the crash

p_f = m₁ v₁ + m₂ v_{2f}

the moment is preserved

p₀ = p_f

m₂ v₂₀ = m₁ v_{1f} + m₂ v_{2f} (2)

m₂ (v₂₀ - v_2f}) = m₁ v_{1f}

as the collision is elastic the kinetic energy is also conserved

K₀ = K_f

½ m₂ v₂₀² = ½ m₁ v_{1f}² + ½ m₂ v_{2f}²

m₂ (v₂₀² -v_{2f}²) = m₁ v_{1f}²

let's write our system of equations, using

a² - b² = (a + b) (a-b)

m₂ (v₂₀ - v_{2f}) = m₁ v_{1f}

m₂ (v₂₀ -v_{2f}) (v₂₀ + v_{2f}) = m₁ v_{1f}²

to solve we divide the equations

v₂₀ + v_{2f} = v_{1f}

with this we substitute in equation 2 and find the speed of each car, in this case we need the speed of car 1

m₂ v₂₀ = m₁ v_{1f} + m₂ (v_{1f}-v₂₀)

2m₂ v₂₀ = (m₁ + m₂) v_{1f}

v_{1f} = $\frac{2m_2}{m_1+m_2} v_{2o}$

We substitute in the drive ratio of car 1

F t = m (v_f -v₀)

F = m₁ (\frac{2m_2}{m_1+m_2} v_{2o} - 0) / t

F = $\frac{2m_1 m_2 }{m_1+m_2} \ \frac{v_{2o}}{t}$

the mass of each car is the mass of the car plus the mass of the boy

m₁ = 50 +40 = 90 kg

m₂ = 50 +60 = 110 kg

time is t = 1

we substitute the values

F = $\frac{ 2\ 90 \ 110}{90+110} \ \frac{v_{2o}}{1}$ 2 90 100/90 + 110 vo2 / 1

F = 99 v₂₀

The value of the initial velocity of car 2 is not indicated in the problem, if this velocity is known it can be included and the force value is obtained, suppose that the initial velocity v₂₀ = 1 m / s

F = 99 N

4 0

3 years ago