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2 years ago

Define the word logrolling in your own words?

Physics

2 answers:

Elan Coil [88]2 years ago

3 0

A crazy sport thats kinda dangerous

Doss [256]2 years ago

3 0

Answer:

Logrolling is the practice of legislators exchanging favors, or quid pro quo, such as vote trading, in order to enact legislation that is of interest to each of them.

<u>OAmalOHopeO</u>

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Compute the kinetic energy of a proton (mass 1.67×10−27kg ) using both the nonrelativistic and relativistic expressions for spee

JulsSmile [24]

Answer:

The non-relativistic kinetic energy of a proton is $6.76\times10^{-12}\ J$

The relativistic kinetic energy of a proton is $7.25\times10^{-12}\ m/s$

Explanation:

Given that,

Mass of proton $m=1.67\times10^{-27}\ kg$

Speed $v= 9.00\times10^{7}\ m/s$

We need to calculate the kinetic energy for non relativistic

Using formula of kinetic energy

$K.E=\dfrac{1}{2}mv^2$

Put the value into the formula

$K.E=\dfrac{1}{2}\times1.67\times10^{-27}\times(9.00\times10^{7})^2$

$K.E=6.76\times10^{-12}\ J$

We need to calculate the kinetic energy for relativistic

Using formula of kinetic energy

$K.E=mc^2(\sqrt{(\dfrac{1}{1-\dfrac{v^2}{c^2}})}-1)$

$K.E=1.67\times10^{-27}\times(3\times10^{8})^{2}\cdot\left(\sqrt{\frac{1}{1-\frac{\left(9.00\times10^{7}\right)^{2}}{(3\times10^{8})^{2}}}}-1\right)$

$K.E=7.25\times10^{-12}\ m/s$

Hence, The non-relativistic kinetic energy of a proton is $6.76\times10^{-12}\ J$

The relativistic kinetic energy of a proton is $7.25\times10^{-12}\ m/s$

7 0

3 years ago

Why are frogs said to have two lives?

Stells [14]

They live half their lives in water and most of their life on land

8 0

3 years ago

Which option most likely describes scientist(s) working in pure science?

lana [24]

Answer:

Two scientists in a lab examining vials of urine they are analyzing for levels of excreted protein.

Explanation:

3 0

2 years ago

Solve for A if F=MA and F=100 and M=25?

inn [45]

Answer:

<h3> $\boxed{ \boxed{ \bold{A = 4}}}$ </h3>

Explanation:

Given,

F = 100 , M = 25

Now, let's find the value of A

$\sf{F = MA}$

plug the values

⇒ $\sf{100 = 25 A}$

Swap the sides of the equation

⇒ $\sf{25A = 100}$

Divide both sides of the equation by 25

⇒ $\sf{ \frac{25A}{25} = \frac{100}{25} }$

Calculate

⇒ $\sf{A = 4}$

Hope I helped!

Best regards!!

5 0

2 years ago

Read 2 more answers

If you travel from Yakima to Ellensburg (Yakima to Ellensburg is 50 miles) with a speed of 60 miles/hour for half of the

koban [17]

Answer:

$\displaystyle \frac{480}{7}\approx 68.6\; \rm mph$ .

Explanation:

The average speed of an object is equal to total distance over total time.

Distance traveled: $\rm 50 \; mi$ .

How much time is taken? This trip is divided into two halves, each of distance $\displaystyle \frac{50}{2} = 25\;\rm mi$ .

Time spent on the first half of the trip:

$\displaystyle t_1 = \frac{s_1}{v_1} = \frac{25}{60} = \frac{5}{12}\; \rm hours$ .

Similarly, time spent on the second half of the trip:

$\displaystyle t_2 = \frac{s_2}{v_2} = \frac{25}{80} = \frac{5}{16}\; \rm hours$ .

In total:

$\displaystyle \frac{5}{12} + \frac{5}{16} = \frac{35}{48} \; \rm hours$ .

Average speed:

$\begin{aligned} \text{Average speed} &= \frac{\text{Total Distance}}{\text{Total Time}}\\ &= 50 \left/\frac{35}{48}\right.\\ &= 50 \cdot \frac{48}{35} \\&= \frac{480}{7}\approx 68.6\; \rm mph \end{aligned}$ .

This value turned out to be slightly different from the average of the speed during the two halves of the journey. The reason is that the object traveled at each speed for a different amount of time. It spent more time at the slower speed, which gives that speed a greater weight in the average. That explains why the average speed is closer to $\rm 60\; mph$ rather than $\rm 80\; mph$ .

3 0

2 years ago