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Sonbull [250]
3 years ago
9

Consider a comet with an elliptic orbit whose aphelion and perihelion distances are rA = 5.00109 km and rP = 8.00107 km. e. Fi

nd the speed of the comet at aphelion and at perihelion

Physics
1 answer:
enyata [817]3 years ago
6 0

Answer:

Explanation:

To find this speed find the attached document below;

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A planet's distance from the sun is 2.0x10^11 m. what is the orbital period?
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The square of the orbital period of a planet is directly proportional to the cube of the semimajor axis of its orbit.

Explanation:

hope this helps.

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2 years ago
Which of the following statements accurately describes work being done.
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Charge is moved of a capacitor

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A university is planning to send an optical telescope into orbit. stuents attending the university will be able to view which of
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Metals in group 2 on the period table most commonly form which type
LuckyWell [14K]

Answer:

alkaline earth metals

Group 2 metals, the alkaline earth metals, have 2 valence electrons, and thus form M2+ ions. The halogens, Group 17 , reach a full valence shell upon reduction, and thus form X− ions

Explanation:

6 0
3 years ago
A physicist's right eye is presbyopic (i.e., farsighted). This eye can see clearly only beyond a distance of 97 cm, which makes
Ivan

Answer:

f = 19,877 cm   and  P = 5D

Explanation:

This is a lens focal length exercise, which must be solved with the optical constructor equation

        1 / f = 1 / p + 1 / q

where f is the focal length, p is the distance to the object and q is the distance to the image.

In this case the object is placed p = 25 cm from the eye, to be able to see it clearly the image must be at q = 97 cm from the eye

let's calculate

        1 / f = 1/97 + 1/25

        1 / f = 0.05

        f = 19,877 cm

the power of a lens is defined by the inverse of the focal length in meters

         P = 1 / f

         P = 1 / 19,877 10-2

         P = 5D

5 0
2 years ago
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