Answer:
Relative roughness = 0.04
Explanation:
Given that:
Diameter = 5 cm
roughness = 2 mm
At inlet:
Minor coefficient loss 
At exit:
Minor coefficient loss 
Height h = 4m
Length = 5 m
To find the relative roughness:
Relative roughness is a term that is used to describe the set of irregularities that exist inside commercial pipes that transport fluids. The relative roughness can be evaluated by knowing the diameter of the pipe made with the absolute roughness in question. If we denote the absolute roughness as e and the diameter as D, the relative roughness is expressed as:



Answer:
8.62m/s²
Explanation:
the particle is experiencing both translational and circular motion
v=4t²
=
=8t
at t=1s,
=8(1)=8m/s²
= 
at t=1, v= 4(1)² = 4m/s
=4²/5
=3.2m/s²
∴ magnitude of total acceleration, a
a=
a=
a=
a=
a=8.62m/s²