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4 years ago

11

Question 1/5

1 answer:

erastova [34]4 years ago

6 0

It’s between D and C

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What part connect to the tie rod that helps the brake chamber out that deals with slack adjuster

scoray [572]

Answer:

none

Explanation:

7 0

2 years ago

A piston–cylinder device contains 15 kg of saturated refrigerant-134a vapor at 280kPa. A resistance heater inside the cylinder w

attashe74 [19]

Answer:

18.77 A

Explanation:

To solve this we use the energy balance equation, that is:

$E_{in}-E_{out}=\Delta E_{sys}\\\\Q_{in}+W_{in}+W_{out}=\Delta U\\\\Q_{in}+W_{in}=\Delta U\\\\But\ W_{in}=Voltage(V)*Current(I)*change\ in\ time(\Delta t)=VI\Delta t,\Delta U=m(h_2-h_1)\\\\Given\ that\ m=15kg,V=110\ V,\Delta t=6\ min = (6*60\ s)=360\ s,Q_{in}=20.67\ kJ/kg*15\ kg=310.05\ kJ=310050\ J\\\\From\ table: At\ P_1=280kPa, h_1=249.71\ kJ/kg=249710\ J/kg;At\ P_2=280kPa \ and\ T_1=75^oC,P_2=319.95\ kJ/kg=319950\ J/kg\\\\Substituting:\\\\310500+(110*360*I)=15(319950-249710)\\\\$

$39600I=1053600-310500\\\\39600I=743100\\\\I=18.77\ A$

3 0

3 years ago

A three-point bending test was performed on an aluminum oxide specimen having a circular cross section of radius 5.0 mm (0.20 in

Sonja [21]

The load is 17156 N.

<u>Explanation:</u>

First compute the flexural strength from:

σ = FL / π $R^{3}$

= 3000 $\times$ (40 $\times$ 10^-3) / π (5 $\times$ 10^-3)^3

σ = 305 $\times$ 10^6 N / m^2.

We can now determine the load using:

F = 2σd^3 / 3L

= 2(305 $\times$ 10^6) (15 $\times$ 10^-3)^3 / 3(40 $\times$ 10^-3)

F = 17156 N.

7 0

4 years ago

State two reasons why industrial files must be always be used fitted upon the individual

NikAS [45]

Explanation:

dnndndndndndndndndnndmfnfnf

4 0

3 years ago

What percentage of the map would have unhealthy levels of arsenic (140 total squares)?

Daniel [21]

Answer:

35

Explanation:

so you said 140 in total and it's a square

it's basically finding the perimeter of the square

so 35 is each side of the square that I am imagining in my head

so if you add 35...4 times you will get 140

for example:35

35

35

+ <u>3</u><u>5</u>

<u>1</u><u>4</u><u>0</u><u> </u>

or 35×4=140

4 0

3 years ago