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Nadusha1986 [10]
3 years ago
9

A Gaussian random voltage X volts is input to a half-wave rectifier and the output voltage is Y = Xu (X) Volts were u (x) is the

unit step function. Assume X has mean 0 V and variance σ^2 V^2. The output voltage Y is then applied across a (nonrandom) resistance of R ohms. The answers below should be expressed in terms of the Φ or Q functions or in closed form (no integrals).
(a) Find the probability that the current which flows through the resistor exceeds 1 Amp.
(b) Find the probability that the power which is dissipated in the resistor exceeds 1 watt.
(c) Find the mean and variance of the current which flows through the resistor.
(d) Find the mean and variance of the power which is dissipated in the resistor.

Engineering
1 answer:
adelina 88 [10]3 years ago
7 0

Answer:

Please look at attachment carefully.

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A rectangular steel bar, with 8" x 0.75" cross-sectional dimensions, has equal and opposite moments applied to its ends.
denpristay [2]

Answer:

Part a: The yield moment is 400 k.in.

Part b: The strain is 8.621 \times 10^{-4} in/in

Part c: The plastic moment is 600 ksi.

Explanation:

Part a:

As per bending equation

\frac{M}{I}=\frac{F}{y}

Here

  • M is the moment which is to be calculated
  • I is the moment of inertia given as

                         I=\frac{bd^3}{12}

Here

  • b is the breath given as 0.75"
  • d is the depth which is given as 8"

                     I=\frac{bd^3}{12}\\I=\frac{0.75\times 8^3}{12}\\I=32 in^4

  • y is given as

                     y=\frac{d}{2}\\y=\frac{8}{2}\\y=4"\\

  • Force is 50 ksi

\frac{M_y}{I}=\frac{F_y}{y}\\M_y=\frac{F_y}{y}{I}\\M_y=\frac{50}{4}{32}\\M_y=400 k. in

The yield moment is 400 k.in.

Part b:

The strain is given as

Strain=\frac{Stress}{Elastic Modulus}

The stress at the station 2" down from the top is estimated by ratio of triangles as

                        F_{2"}=\frac{F_y}{y}\times 2"\\F_{2"}=\frac{50 ksi}{4"}\times 2"\\F_{2"}=25 ksi

Now the steel has the elastic modulus of E=29000 ksi

Strain=\frac{Stress}{Elastic Modulus}\\Strain=\frac{F_{2"}}{E}\\Strain=\frac{25}{29000}\\Strain=8.621 \times 10^{-4} in/in

So the strain is 8.621 \times 10^{-4} in/in

Part c:

For a rectangular shape the shape factor is given as 1.5.

Now the plastic moment is given as

shape\, factor=\frac{Plastic\, Moment}{Yield\, Moment}\\{Plastic\, Moment}=shape\, factor\times {Yield\, Moment}\\{Plastic\, Moment}=1.5\times400 ksi\\{Plastic\, Moment}=600 ksi

The plastic moment is 600 ksi.

3 0
3 years ago
A set of bus bars also can be called a
Vikki [24]

Answer:

hi

Explanation:

3 0
3 years ago
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Will a simple circuit work without a switch? Explain why or why not.
Marina CMI [18]

yes, a simple circuit will work without a switch. If we don't have a switch in a circuit then whichever device you are using electricity for wouldn't be able to switch off and will be working continuously. An open/close switch is usually all that is needed to supply or disconnect power from the source to the circuit.So, the circuit will work but it will work continuously.

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2 years ago
Which statement best describes the lower vc-turbo engine compression ratios?.
kobusy [5.1K]

The statement that best describes the lower vc-turbo engine compression ratios is that its generate an increased amount of power with the average fuel consumption.

<h3>Vc-turbo engine</h3>

In the engine, lower temperatures allow to run more ignition timing advance which makes significantly more power than increasing the compression ratio in a turbo engine.

Hence, the turbo engines run lower static compression ratios to increase the amount of power they can reliable generate on pump gas.

Therefore, the statement that best describes the lower vc-turbo engine compression ratios is that its generate an increased amount of power with the average fuel consumption.

Read more about turbo engines

<em>brainly.com/question/26409491</em>

7 0
2 years ago
Subscribe to my channel RitzyAirplane71​
frez [133]

Answer:

okay!

Explanation:

if you don't mind marking my answer brainiest

7 0
2 years ago
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