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3 years ago

List six clues that indicates that you are approaching an intersection

Engineering

1 answer:

nydimaria [60]3 years ago

6 0

Answer:

the answer is C

Explanation:

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Steam enters a heavily insulated throttling valve at 11 MPa, 600Â°C and exits at 5.5 MPa. Determine the final temperature of the

7nadin3 [17]

Answer: the final temperature of the steam 581.5 °C

Explanation:

Given that;

P₁ = 11 MPa

T₁ = 600°C

exit at; P₂= 5.5 MPa

Now from superheated steam table( p=11 MPa, T=600°C)

h₁ = 3615 kJ/kg

h₁ = h₂ ( by throttling process and adiabatic isentholpic )

from saturated steam table at; ( h= 3615 kJ/kg, P= 5.5 MPa )

Temperature = 581.5 °C

Therefore the final temperature of the steam 581.5 °C

8 0

3 years ago

Thermodynamics fill in the blanks The swimming pool at the local YMCA holds roughly 749511.5 L (749511.5 kg) of water and is kep

Talja [164]

Answer:

$95.914\ \text{GJ}$

$\$272.78$

Explanation:

m = Mass of water = 749511.5 kg

c = Specific heat of water = 4182 J/kg ⋅°C

$\Delta T$ = Change in temperature = $80.6-50=30.6^{\circ}\text{F}$

Cost of 1 GJ of energy = $2.844

Heat required is given by

$Q=mc\Delta T\\\Rightarrow Q=749511.5\times 4182\times 30.6\\\Rightarrow Q=95.914\times 10^9\ \text{J}=95.914\ \text{GJ}$

Amount of heat required to heat the water is $95.914\ \text{GJ}$ .

Cost of heating the water is

$95.914\times 2.844=\$272.78$

Cost of heating the water to the required temperature is $\$272.78$ .

7 0

3 years ago

A very large plate is placed equidistant between two vertical walls. The 10-mm spacing between the plate and each wall is filled

Vikentia [17]

Answer:

Force per unit plate area is 0.1344 $N/m^{2}$

Solution:

As per the question:

The spacing between each wall and the plate, d = 10 mm = 0.01 m

Absolute viscosity of the liquid, $\mu =1.92\times 10^{- 3} Pa-s$

Speed, v = 35 mm/s = 0.035 m/s

Now,

Suppose the drag force that exist between each wall and plate is F and F' respectively:

Net Drag Force = F' + F''

$F = \tau A$

where

$\tau$ = shear stress

A = Cross - sectional Area

Therefore,

Net Drag Force, F = $(\tau ' +\tau '')A$

$\frac{F}{A} = \tau ' +\tau ''$

Also

F = $\frac{\mu v}{d}$

where

$\mu$ = dynamic coefficient of viscosity

Pressure, P = $\frac{F}{A}$

Therefore,

$\frac{F}{A} = \frac{\mu v}{d} + \frac{\mu v}{d} = 2\frac{\mu v}{d}$

$\frac{F}{A} = 2\frac{1.92\times 10^{- 3}\times 0.035}{0.010} = 0.01344 N/m^{2}$

8 0

3 years ago

Find the mass if the force is 18 N and the acceleration is 2 m/s2

Nana76 [90]

Explanation:

f = ma

m = f/a

= 18N / 2m/s2

= 9kg

5 0

3 years ago

Read 2 more answers

A plumbed eyewash station is portable.

Hitman42 [59]

Plumbed stations are permanently connected to a source of potable water, whereas portable stations are self-contained gravity-fed units with their own flushing fluid that must be replaced after each use. ... Eyewash fluid must irrigate and flush both eyes simultaneously.
Hopefully this helped.

8 0

3 years ago