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k0ka [10]
3 years ago
10

List six clues that indicates that you are approaching an intersection

Engineering
1 answer:
nydimaria [60]3 years ago
6 0

Answer:

the answer is C

Explanation:

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Steam enters a heavily insulated throttling valve at 11 MPa, 600°C and exits at 5.5 MPa. Determine the final temperature of the
7nadin3 [17]

Answer: the final temperature of the steam 581.5 °C

Explanation:

Given that;

P₁ = 11 MPa

T₁ = 600°C

exit at; P₂= 5.5 MPa

Now from superheated steam table( p=11 MPa, T=600°C)

h₁ = 3615 kJ/kg  

h₁ = h₂ ( by throttling process and adiabatic isentholpic )

from saturated steam table at; ( h= 3615 kJ/kg, P= 5.5 MPa )

Temperature = 581.5 °C

Therefore the final temperature of the steam 581.5 °C

8 0
3 years ago
Thermodynamics fill in the blanks The swimming pool at the local YMCA holds roughly 749511.5 L (749511.5 kg) of water and is kep
Talja [164]

Answer:

95.914\ \text{GJ}

\$272.78

Explanation:

m = Mass of water = 749511.5 kg

c = Specific heat of water = 4182 J/kg ⋅°C

\Delta T = Change in temperature = 80.6-50=30.6^{\circ}\text{F}

Cost of 1 GJ of energy = $2.844

Heat required is given by

Q=mc\Delta T\\\Rightarrow Q=749511.5\times 4182\times 30.6\\\Rightarrow Q=95.914\times 10^9\ \text{J}=95.914\ \text{GJ}

Amount of heat required to heat the water is 95.914\ \text{GJ}.

Cost of heating the water is

95.914\times 2.844=\$272.78

Cost of heating the water to the required temperature is \$272.78.

7 0
3 years ago
A very large plate is placed equidistant between two vertical walls. The 10-mm spacing between the plate and each wall is filled
Vikentia [17]

Answer:

Force per unit plate area is 0.1344 N/m^{2}

Solution:

As per the question:

The spacing between each wall and the plate, d = 10 mm = 0.01 m

Absolute viscosity of the liquid, \mu =1.92\times 10^{- 3} Pa-s

Speed, v = 35 mm/s = 0.035 m/s

Now,

Suppose the drag force that exist between each wall and plate is F and F' respectively:

Net Drag Force = F' + F''

F = \tau A

where

\tau = shear stress

A = Cross - sectional Area

Therefore,

Net Drag Force, F = (\tau ' +\tau '')A

\frac{F}{A} = \tau ' +\tau ''

Also

F = \frac{\mu v}{d}

where

\mu = dynamic coefficient of viscosity

Pressure, P = \frac{F}{A}

Therefore,

\frac{F}{A} = \frac{\mu v}{d} + \frac{\mu v}{d} = 2\frac{\mu v}{d}

\frac{F}{A} = 2\frac{1.92\times 10^{- 3}\times 0.035}{0.010} = 0.01344 N/m^{2}

8 0
3 years ago
Find the mass if the force is 18 N and the acceleration is 2 m/s2
Nana76 [90]

Explanation:

f = ma

m = f/a

= 18N / 2m/s2

= 9kg

5 0
3 years ago
Read 2 more answers
A plumbed eyewash station is portable.
Hitman42 [59]
Plumbed stations are permanently connected to a source of potable water, whereas portable stations are self-contained gravity-fed units with their own flushing fluid that must be replaced after each use. ... Eyewash fluid must irrigate and flush both eyes simultaneously.
Hopefully this helped.
8 0
3 years ago
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